The total translational kinetic energy of the molecules of a sample of gas at 415 K is 17500 J. How many moles n does the sample comprise? n = mol Find the average translational kinetic energy K, of a single molecule. Ky = J

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The total translational kinetic energy of the molecules of a sample of gas at 415 K is 17500 J. How many moles n does the
sample comprise?
mol
n =
Find the average translational kinetic energy Ky of a single molecule.
J
Kav
Transcribed Image Text:The total translational kinetic energy of the molecules of a sample of gas at 415 K is 17500 J. How many moles n does the sample comprise? mol n = Find the average translational kinetic energy Ky of a single molecule. J Kav
Expert Solution
Step 1

Given that

           The total Translational kinetic energy(K.E) = 17500J

           Temperature (T) = 415K

According to the kinetic theory of the gases, The translational Kinetic energy of the molecules is given by

                         K.E = 3n2RT

Where n is the number of the moles and R is a gas constant ( R = 8.3145J/mole-K)

putting all the given values in the above equation, we get

                        17500 = 32n×8.1345×415n = 3.5mol

                           

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