Consider a pressure versus volume graph, where the differentcurves represent different processes done on a gas. Starting atthe origin to point 1, the pressure and volume are increased to2.500 x 10° Pa and 4.08 m³, respectively. From 1 to 2, thegas expands at constant pressure to a volume of 7.08 m³.3From 2 to 3, the pressure rises to 4082 Pa. Finally, from 3 to4, the gas expands again to 10.51 m³.Rank the curves from the most positive to the most negativeamount of work done on the gas.1Most positive work3-4Volume (m³)0-11-22–3Most negative workAnswer BankIncorrectWhat is the total work done on the gas?Wo-4JIncorrectPressure (Pa)

Answered: Image /qna-images/answer/92960138-515e-4ffc-a740-df81d6e55406.jpg

Consider a pressure versus volume graph, where the different curves represent different processes done on a gas. Starting at the origin to point 1, the pressure and volume are increased to 2.500 x 103 Pa and 4.08 m³, respectively. From 1 to 2, the gas expands at constant pressure to a volume of 7.08 m³. 3 4 From 2 to 3, the pressure rises to 4082 Pa. Finally, from 3 to 4, the gas expands again to 10.51 m³. Rank the curves from the most positive to the most negative amount of work done on the gas. 1 2 Most positive work 3-4 Volume (m³) 0–1 1-2 2–3 Most negative work Answer Bank Incorrect What is the total work done on the gas? Wo-4 = J Incorrect Pressure (Pa)

Consider a pressure versus volume graph, where the different curves represent different processes done on a gas. Starting at the origin to point 1, the pressure and volume are increased to 2.500 x 103 Pa and 4.08 m³, respectively. From 1 to 2, the gas expands at constant pressure to a volume of 7.08 m³. 3 4 From 2 to 3, the pressure rises to 4082 Pa. Finally, from 3 to 4, the gas expands again to 10.51 m³. Rank the curves from the most positive to the most negative amount of work done on the gas. 1 2 Most positive work 3-4 Volume (m³) 0–1 1-2 2–3 Most negative work Answer Bank Incorrect What is the total work done on the gas? Wo-4 = J Incorrect Pressure (Pa)

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

Suppose you have 0.53 moles of an ideal gas. What is the average kinetic energy of that gas (in units of kJ) if the temperature of the gas is 280.2K? Note: It is understood that the unit of your answer is some number of kilo-Joules, however do not explicitly include units in your answer. Enter only a number. If you do enter a unit ("kJ" in this case), you answer will be counted wrong.
One mole of an ideal gas does 1700 J of work as it expands isothermally to a final pressure of 1.00 × 105 Pa and volume of 0.031 m3 a) what was the inital volume of the gas in cubic meters? b) what is the tempature of gas in kelvin
Please complete full question. The answer is of no use without it.
0.0035 mol of gas undergoes the process shown in . (B) What is the initial temperature? (C) What is the final temperature?
-80J of work are done on the gas in the process shown in (Figure 1). Figure p (kPa) P₁- 0 0 100 200 300 1 of 1 V (cm³) Part A What is p₁ in kPa? Express your answer in kilopascals. P1 = Submit IVE ΑΣΦ Provide Feedback Previous Answers Request Answer ? kPa
Homework 4, Problem 3 Part (a) For n = 1 moles, T = 305 K, and V2 = 3.5V1, determine the work done by the gas on the external body. The gas constant is R = 8.314 J K-1 mol-1. W = ______
The heat engine shown in the figure uses 2.0 mol of a monatomic gas as the working substance. (Figure 1) Figure p (kPa) 600 400 200- 0 0 0.025 0.050 V (m³) Part A Determine T₁, T₂, and T₁. Enter your answers numerically separated by commas. Express your answer using two significant figures. T₁ T₂. T₂ = 600,1800,1200 K Submit Previous Answers ✓ Correct Part B Determine AEth. W. and Q for 1-2. Enter your answers numerically separated by commas. Express your answer using two significant figures. AEth. Ws. Q = 3.0x104.1.3x104.4.3x104 J Submit ✓ Correct ▾ Part C Previous Answers Determine AEth. W. and Q for 2-3. Enter your answers numerically separated by commas. Express your answer using two significant figures. AEth. Ws. Q= Submit ▾ Part D ΠΑΣΦ Request Answer I ? J
4.5 mol of monatomic gas A interacts with 2.9 mol of monatomic gas B. Gas A initially has 9000 J of thermal energy, but in the process of coming to thermal equilibrium it transfers 800 J of heat energy to gas B. How much thermal energy did gas B have initially? Express your answer with the appropriate units. ► View Available Hint(s) EBi = Submit Value 4 Previous Answers Units ?
Estilos Edición P5. A rigid container contains water vapor at 250°C and an unknown pressure. When the container cools to 150°C, the vapor begins to condense. Estimate the initial pressure in the container. Plot the thermodynamic process on a phase diagram. Answer: 600 kPa.
-70 J of work are done on the gas in the process shown in (Figure 1). Figure p (kPa) P₁ 0+ 0 100 200 300 < 1 of 1 V (cm³) Part A What is p₁ in kPa? Express your answer in kilopascals. P1 = Submit VE ΑΣΦ Provide Feedback Request Answer ***** ? kPa
When gas expands in a cylinder with radius r, the pressure P at any given time is a function of the volume V: P = P(V). The force exerted by the gas on the piston (see the figure) is the product of the pressure and the area: F = πr²p. piston head V x The work done by the gas when the volume expands from volume V₁ to volume V2 is as follows. 1 W = dv In a steam engine the pressure and volume of steam satisfy the equation PV1.4 = k, where k is a constant. (This is true for adiabatic expansion, that is, expansion in which there is no heat transfer between the cylinder and its surroundings.) Calculate the work done by the engine during a cycle when the steam starts at a pressure of 180 lb/in² and a volume of 500 in³ and expands to a volume of 700 in³. (Round your answer to two decimal places.) W = X ft-lb
Answer: −465.584 J