One mole of helium atoms has a mass of 4 grams. If a helium atom in a balloon has a kinetic energy of 1.666e-21 J, what is the speed of the helium atom? (The speed is much lower than the speed of light.) V = m/s Additional Materials

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Problem Statement:**

One mole of helium atoms has a mass of 4 grams. If a helium atom in a balloon has a kinetic energy of \(1.666 \times 10^{-21}\) J, what is the speed of the helium atom? (The speed is much lower than the speed of light.)

\[ v = \_\_\_\_ \, \text{m/s} \]

**Additional Materials:**

- eBook

**Explanation:**

This problem involves calculating the speed of a helium atom given its kinetic energy. The formula for kinetic energy (\(KE\)) in terms of mass (\(m\)) and velocity (\(v\)) is:

\[ KE = \frac{1}{2} m v^2 \]

By rearranging this formula, we can solve for \(v\):

\[ v = \sqrt{\frac{2 \times KE}{m}} \]

Note that the mass of a single helium atom must be determined using the given information that one mole of helium has a mass of 4 grams. This requires converting the mass from grams per mole to kilograms for a single atom, using Avogadro's number.
Transcribed Image Text:**Problem Statement:** One mole of helium atoms has a mass of 4 grams. If a helium atom in a balloon has a kinetic energy of \(1.666 \times 10^{-21}\) J, what is the speed of the helium atom? (The speed is much lower than the speed of light.) \[ v = \_\_\_\_ \, \text{m/s} \] **Additional Materials:** - eBook **Explanation:** This problem involves calculating the speed of a helium atom given its kinetic energy. The formula for kinetic energy (\(KE\)) in terms of mass (\(m\)) and velocity (\(v\)) is: \[ KE = \frac{1}{2} m v^2 \] By rearranging this formula, we can solve for \(v\): \[ v = \sqrt{\frac{2 \times KE}{m}} \] Note that the mass of a single helium atom must be determined using the given information that one mole of helium has a mass of 4 grams. This requires converting the mass from grams per mole to kilograms for a single atom, using Avogadro's number.
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