One mole of helium atoms has a mass of 4 grams. If a helium atom in a balloon has a kinetic energy of 1.666e-21 J, what is the speed of the helium atom? (The speed is much lower than the speed of light.) V = m/s Additional Materials
One mole of helium atoms has a mass of 4 grams. If a helium atom in a balloon has a kinetic energy of 1.666e-21 J, what is the speed of the helium atom? (The speed is much lower than the speed of light.) V = m/s Additional Materials
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Problem Statement:**
One mole of helium atoms has a mass of 4 grams. If a helium atom in a balloon has a kinetic energy of \(1.666 \times 10^{-21}\) J, what is the speed of the helium atom? (The speed is much lower than the speed of light.)
\[ v = \_\_\_\_ \, \text{m/s} \]
**Additional Materials:**
- eBook
**Explanation:**
This problem involves calculating the speed of a helium atom given its kinetic energy. The formula for kinetic energy (\(KE\)) in terms of mass (\(m\)) and velocity (\(v\)) is:
\[ KE = \frac{1}{2} m v^2 \]
By rearranging this formula, we can solve for \(v\):
\[ v = \sqrt{\frac{2 \times KE}{m}} \]
Note that the mass of a single helium atom must be determined using the given information that one mole of helium has a mass of 4 grams. This requires converting the mass from grams per mole to kilograms for a single atom, using Avogadro's number.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F877d147a-40f9-47d8-b25c-41d77d376d71%2F369132b0-4b21-4883-a504-4031a3742040%2Fyv8qan_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
One mole of helium atoms has a mass of 4 grams. If a helium atom in a balloon has a kinetic energy of \(1.666 \times 10^{-21}\) J, what is the speed of the helium atom? (The speed is much lower than the speed of light.)
\[ v = \_\_\_\_ \, \text{m/s} \]
**Additional Materials:**
- eBook
**Explanation:**
This problem involves calculating the speed of a helium atom given its kinetic energy. The formula for kinetic energy (\(KE\)) in terms of mass (\(m\)) and velocity (\(v\)) is:
\[ KE = \frac{1}{2} m v^2 \]
By rearranging this formula, we can solve for \(v\):
\[ v = \sqrt{\frac{2 \times KE}{m}} \]
Note that the mass of a single helium atom must be determined using the given information that one mole of helium has a mass of 4 grams. This requires converting the mass from grams per mole to kilograms for a single atom, using Avogadro's number.
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