14. Assume you have the following stock solutions: 1 M Tris-HCl (pH 8.0) 0.5 M EDTA (pH 8.0) Perform the calculations and state how would you make 30 mL of TE buffer, which has the following in a single tube: 10 mM Tris-HCl (pH8.0) 1 mM EDTA

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10:23
14. Assume you have the following stock solutions:
1 M Tris-HCl (pH 8.0)
0.5 M EDTA (pH 8.0)
LTE
Perform the calculations and state how would you make 30 mL of TE buffer, which has the
following in a single tube:
10 mM Tris-HCl (pH8.0)
1 mM EDTA
X
Transcribed Image Text:10:23 14. Assume you have the following stock solutions: 1 M Tris-HCl (pH 8.0) 0.5 M EDTA (pH 8.0) LTE Perform the calculations and state how would you make 30 mL of TE buffer, which has the following in a single tube: 10 mM Tris-HCl (pH8.0) 1 mM EDTA X
Expert Solution
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Ans:-

Explanation:- Given that there is a need to form 30 ml of TE buffer.

TE buffer is a solution where Tris HCl is 10 times in concentration to the EDTA. 

This question can be solved from a simple formula:-

M1V1 = M2V2, Where M1 is the initial molarity of the chemical

M2 is the final molarity of the chemical.

V1 is the initial volume of the chemical and 

V2 is the final volume of the chemical.

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