Calculate the of the acetic acid in for each – show all unit conversions (hint: start with mL of and use the on page 2). Trial2 Trial 1 a).3L Volume of vinegar 5.00 mL 5.00 mL Initial burette reading a0omL 21.00ML Final burette reading 43.9mL neotia.5- Volume of base used 22.9 Temp TO a 21.00ML 21.00ML Hezy za H IA its pres Trial 1: Trial 2: Average: Ose the average molarity above, and a density of 1.12 g/mL for the vinegar, calculate the % acetic acid (w/w) using dimensional analysis (hint: try starting with the average molarity of acetic acid in the vinegar).
Calculate the of the acetic acid in for each – show all unit conversions (hint: start with mL of and use the on page 2). Trial2 Trial 1 a).3L Volume of vinegar 5.00 mL 5.00 mL Initial burette reading a0omL 21.00ML Final burette reading 43.9mL neotia.5- Volume of base used 22.9 Temp TO a 21.00ML 21.00ML Hezy za H IA its pres Trial 1: Trial 2: Average: Ose the average molarity above, and a density of 1.12 g/mL for the vinegar, calculate the % acetic acid (w/w) using dimensional analysis (hint: try starting with the average molarity of acetic acid in the vinegar).
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
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The molarity of naoh is 0.1715

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Transcribed Image Text:**Vinegar Data for % Acetic Acid**
- **Volume of Vinegar (ml):** 5.00
- **Volume of Base (mL):** 21.00
- **Acid Molarity (M):** 0.8001, 0.874 M
- **% Acid:** 4.81%, 5.25%
**Instructions:**
1. Trial
2. Use the average molarity and dimensional analysis
The document appears to involve a calculation of acetic acid concentration in vinegar through titration, comparing different trials for consistency.
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