13.19 .. A planet orbiting a distant star has radius 3.24 × 106 m. The escape speed for an object launched from this planet's surface is 7.65 103 m/s. What is the acceleration due to gravity at the surface of the planet? Conservation of energy K1 +U1 = K2 + U2 Gravitational PE = - GMm/r; g = GM/r² When an object escapes from the gravitational field U = 0 at very far from the planet K =0 g = 9.03 m/s²

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter11: Gravity, Planetary Orbits, And The Hydrogen Atom
Section: Chapter Questions
Problem 36P
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I need help with this problem and an explanation of why its the answer described below:

(g = 9.03 m/s^2 is the answer but I need an explanations as to why it's the answer.)

13.19 .. A planet orbiting a distant star has radius 3.24 × 106 m.
The escape speed for an object launched from this planet's surface
is 7.65 103 m/s. What is the acceleration due to gravity at the
surface of the planet?
Conservation of energy K1 +U1 = K2 + U2
Gravitational PE = - GMm/r; g = GM/r²
When an object escapes from the gravitational field U = 0 at very far from the planet K =0
g = 9.03 m/s²
Transcribed Image Text:13.19 .. A planet orbiting a distant star has radius 3.24 × 106 m. The escape speed for an object launched from this planet's surface is 7.65 103 m/s. What is the acceleration due to gravity at the surface of the planet? Conservation of energy K1 +U1 = K2 + U2 Gravitational PE = - GMm/r; g = GM/r² When an object escapes from the gravitational field U = 0 at very far from the planet K =0 g = 9.03 m/s²
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