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A rubber band is under tension in equilibrium, modeled by the equation t 1 = AT (12 - 1/1) \x2 With t as the tension, T is the absolute temperature, x length of the band, lo is the legth of the band without tension, and A is constant. The thermal capacity at x=lo is cx(x=lo,T) = K, with K as constant. (a) Solve the following as a function of x and T (JE) (i) (ii) (bcx)T (iii) cx(x,T) (iv) E(x,T) and (v) S(x,T) Where E is the energy and S is entropy (b) If the band is stretched adiabatically from x=lo to x=1.510, what is its final temperature?

A rubber band is under tension in equilibrium, modeled by the equation t 1 = AT (12 - 1/1) \x2 With t as the tension, T is the absolute temperature, x length of the band, lo is the legth of the band without tension, and A is constant. The thermal capacity at x=lo is cx(x=lo,T) = K, with K as constant. (a) Solve the following as a function of x and T (JE) (i) (ii) (bcx)T (iii) cx(x,T) (iv) E(x,T) and (v) S(x,T) Where E is the energy and S is entropy (b) If the band is stretched adiabatically from x=lo to x=1.510, what is its final temperature?

University Physics Volume 2
University Physics Volume 2
18th Edition
ISBN:9781938168161
Author:OpenStax
Publisher:OpenStax
Chapter2: The Kinetic Theory Of Gases
Section: Chapter Questions
Problem 81AP: One process for decaffeinating coffee uses carbon dioxide ( M=44.0 g/mol) at a molar density of...
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A rubber band is under tension in equilibrium, modeled by the equation t 1 = AT (12 - 1/1) \x2 With t as the tension, T is the absolute temperature, x length of the band, lo is the legth of the band without tension, and A is constant. The thermal capacity at x=lo is cx(x=lo,T) = K, with K as constant. (a) Solve the following as a function of x and T (JE) (i) (ii) (bcx)T (iii) cx(x,T) (iv) E(x,T) and (v) S(x,T) Where E is the energy and S is entropy (b) If the band is stretched adiabatically from x=lo to x=1.510, what is its final temperature?
Transcribed Image Text:A rubber band is under tension in equilibrium, modeled by the equation t 1 = AT (12 - 1/1) \x2 With t as the tension, T is the absolute temperature, x length of the band, lo is the legth of the band without tension, and A is constant. The thermal capacity at x=lo is cx(x=lo,T) = K, with K as constant. (a) Solve the following as a function of x and T (JE) (i) (ii) (bcx)T (iii) cx(x,T) (iv) E(x,T) and (v) S(x,T) Where E is the energy and S is entropy (b) If the band is stretched adiabatically from x=lo to x=1.510, what is its final temperature?
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