Homework Help is Here – Start Your Trial Now!
Science
Physics
A particle of charge q = -8µC moves with a velocity v₁ = 5.1×105 m/s at an angle 0 = 35° from the positive y-axis in the positive yz-plane (see figure a). A uniform magnetic field B₁ is in the positive z-direction and it exerts a force П₁ with a magnitude of 0.25 N on the charge. Ꮓ X B₁ v1 Ꮎ y a) The x-component of the velocity v₁ is: 0 b) The y-component of the velocity ₁ is about: 418,000 c) The z-component of the velocity ₁ is about: 292,400 m/s m/s m/s d) The x-, y-, and z-components of the magnetic field vector В₁ are, respectively: [Select] e) The direction of the force ₁ is [Select] f) The angle between the force F₁ and the field B₁is: [Select] g) The magnitude of the magnetic field B₁ is about: [Select] T 0 The same charge q = -8µC now moves with a velocity v2 = 9.1×105 m/s along the positive x-axis in the magnetic field B₂ = (0.06 T) Â (see figure b). h) The magnitude of a force F₂ that В₂ exerts on the charge is about: [Select] N

A particle of charge q = -8µC moves with a velocity v₁ = 5.1×105 m/s at an angle 0 = 35° from the positive y-axis in the positive yz-plane (see figure a). A uniform magnetic field B₁ is in the positive z-direction and it exerts a force П₁ with a magnitude of 0.25 N on the charge. Ꮓ X B₁ v1 Ꮎ y a) The x-component of the velocity v₁ is: 0 b) The y-component of the velocity ₁ is about: 418,000 c) The z-component of the velocity ₁ is about: 292,400 m/s m/s m/s d) The x-, y-, and z-components of the magnetic field vector В₁ are, respectively: [Select] e) The direction of the force ₁ is [Select] f) The angle between the force F₁ and the field B₁is: [Select] g) The magnitude of the magnetic field B₁ is about: [Select] T 0 The same charge q = -8µC now moves with a velocity v2 = 9.1×105 m/s along the positive x-axis in the magnetic field B₂ = (0.06 T) Â (see figure b). h) The magnitude of a force F₂ that В₂ exerts on the charge is about: [Select] N

Principles of Physics: A Calculus-Based Text
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter22: Magnetic Forces And Magnetic Fields
Section: Chapter Questions
Problem 63P
See similar textbooks
icon
Related questions
Question
A particle of charge q = -8µC moves with a velocity v₁ = 5.1×105 m/s at an angle 0 = 35° from the positive y-axis in the positive yz-plane (see figure a). A uniform magnetic field B₁ is in the positive z-direction and it exerts a force П₁ with a magnitude of 0.25 N on the charge. Ꮓ X B₁ v1 Ꮎ y a) The x-component of the velocity v₁ is: 0 b) The y-component of the velocity ₁ is about: 418,000 c) The z-component of the velocity ₁ is about: 292,400 m/s m/s m/s d) The x-, y-, and z-components of the magnetic field vector В₁ are, respectively: [Select] e) The direction of the force ₁ is [Select] f) The angle between the force F₁ and the field B₁is: [Select] g) The magnitude of the magnetic field B₁ is about: [Select] T 0 The same charge q = -8µC now moves with a velocity v2 = 9.1×105 m/s along the positive x-axis in the magnetic field B₂ = (0.06 T) Â (see figure b). h) The magnitude of a force F₂ that В₂ exerts on the charge is about: [Select] N
Transcribed Image Text:A particle of charge q = -8µC moves with a velocity v₁ = 5.1×105 m/s at an angle 0 = 35° from the positive y-axis in the positive yz-plane (see figure a). A uniform magnetic field B₁ is in the positive z-direction and it exerts a force П₁ with a magnitude of 0.25 N on the charge. Ꮓ X B₁ v1 Ꮎ y a) The x-component of the velocity v₁ is: 0 b) The y-component of the velocity ₁ is about: 418,000 c) The z-component of the velocity ₁ is about: 292,400 m/s m/s m/s d) The x-, y-, and z-components of the magnetic field vector В₁ are, respectively: [Select] e) The direction of the force ₁ is [Select] f) The angle between the force F₁ and the field B₁is: [Select] g) The magnitude of the magnetic field B₁ is about: [Select] T 0 The same charge q = -8µC now moves with a velocity v2 = 9.1×105 m/s along the positive x-axis in the magnetic field B₂ = (0.06 T) Â (see figure b). h) The magnitude of a force F₂ that В₂ exerts on the charge is about: [Select] N
Expert Solution
steps

Step by step

Solved in 2 steps

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Principles of Physics: A Calculus-Based Text
Principles of Physics: A Calculus-Based Text
Physics
ISBN:
9781133104261
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
College Physics
College Physics
Physics
ISBN:
9781285737027
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics Volume 2
University Physics Volume 2
Physics
ISBN:
9781938168161
Author:
OpenStax
Publisher:
OpenStax
Physics for Scientists and Engineers
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Physics for Scientists and Engineers with Modern …
Physics for Scientists and Engineers with Modern …
Physics
ISBN:
9781337553292
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
SEE MORE TEXTBOOKS