12. A standard base was established by accurately measuring with a steel tape the distance between fixed marks on a level bed. The mean distance recorded was 24.984 m at a temperature of 18°C and an applied tension of 155 N. The tape used had recently been standardized in catenary and was 30 m in length at 20°C and 100 N tension. Calculate the true length between the fixed marks given: total weight of the tape = 0.90 kg; coefficient of expansion of steel = 11×10“per °C; cross-sectional area = 2 mm²; E=210×10'N/mm²; gravitational acceleration = 9.807 m/s².
12. A standard base was established by accurately measuring with a steel tape the distance between fixed marks on a level bed. The mean distance recorded was 24.984 m at a temperature of 18°C and an applied tension of 155 N. The tape used had recently been standardized in catenary and was 30 m in length at 20°C and 100 N tension. Calculate the true length between the fixed marks given: total weight of the tape = 0.90 kg; coefficient of expansion of steel = 11×10“per °C; cross-sectional area = 2 mm²; E=210×10'N/mm²; gravitational acceleration = 9.807 m/s².
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:12. A standard base was established by accurately measuring with a steel tape the distance
between fixed marks on a level bed. The mean distance recorded was 24.984 m at a
temperature of 180C and an applied tension of 155 N. The tape used had recently been
standardized in catenary and was 30 m in length at 20°C and 100 N tension. Calculate the
true length between the fixed marks given: total weight of the tape = 0.90 kg; coefficient of
expansion of steel = 11×10“per •C; cross-sectional area = 2 mm²; E=210×10³N/mm²;
gravitational acceleration = 9.807 m/s².
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