(12 Marks)Q1) Attempt two only1) For this circuit shown in fig. 1, explain how theoscillation begin?2) Design RTL NOR with two inputs that gives thefollowing values (L.S. = 8.8V, T.W. = 2.6V anddissipation power (avg.) = 29.7mW).Let (VCE (sat) = 0.2V, VBE (FA) = 0.6V,VBE (sat) 0.8V, and BF = 300).3) Explain (555 IC)?5 volt8 voltRA15DISCHARGERB THRESHOLD5 voltRESET 146RTRIGGEROUToutput

Answered: Image /qna-images/answer/b5dde2ab-309b-475a-80dc-ac55f48c8339.jpg

Answered: (12 Marks) Q1) Attempt two only 1) For…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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At any point on the characteristics the product of VCE and IC must be equal to 300 mW. If we choose IC to be the maximum value of 50 mA and substitute into the relationship above, we obtain VCE=? VCEIC = 300 mW a. Reverse bias (J1) and Forward bias (J2) b. Forward bias (J1) and Reverse bias (J2) c.Reverse bias (J1) and Reverse bias (J2) d. Forward bias (J1) and Forward bias (J2)
Prob 1: For each of the 8 circuits below, draw small signal model and calculate Vout/Vin. Vb1, Vb2 are dc voltage sources, and I1 is an ideal de current source. Ignore body effect for all problems. Vb₁k Vb2 VinM₂ VDD M3 = (e) M₁ Vout M3 VDD Vout o Vb1M₂ VinM₁ (f) M3 Vino VDD Vb1M₂ M₁ (g) Vout Vin M3 M₂ M₁ (h) VDD o Vout 1₁
Using the re model circuit, determine the total voltage gain for the BJT circuit shown below. Show the details of your work. 22V ... 5.6k0 330k Vo + 10UF-POL B = 80 1200 10UF-POL To = 40 kN 2N2221 6.8k) Vs 4700 22UF-POL
Prob 1: For each of the 8 circuits below, draw small signal model and calculate Vout/Vin. Vb1, Vb2 are dc voltage sources. and I1 is an ideal dc current source. Ignore body effect for all problems. Vino M3 M₂ M₁ (a) VDD J Vb₁ M3 (e) VDD VinM₂ Vb2M₁ Vb3 Vb2 - Vout Vb1 Vout HE Vout o Vb₁ VinM₂ 46! M3 (b) VDD B M₁ T. M3H (f) VDD VinM₁ M₂ Vout VinM₂ 4M₁ (c) M3 M3 VDD VDD 74 Vb1M₂ Vino M₁ (g) Vout Vout Vb1 Vb2 HE Vin VinM₂ M3 M3 VDD (d) HL M₁ M₁ -o Vout M2o Vout 1₁ (h) VDD
Label properly the required final circuit and DC loadline. Complete the given BJT circuit. Solve for the value of the resistors and voltage supply that will satisfy the given loadline
Solve F
A simple circuit using an NMOS transistor is snown in the on as an amplifier. The input signal is vs, and the output signal is ip (mA) 40 RDmaz = 30 20 the output voltage for a given input voltage. The load line is a | Kirchhoff's voltage law around the drain loop. By plotting this line he intersection of the two graphs. An example of the resulting graph 10 Load line Part B - Choose the drain resistor ΠΠ ΑΣΦ 333.3 5 Submit Previous Answers Hilt ↓↑ vec 3 V GG X Incorrect; Try Again; 5 attempts remaining 10 RD W Ω Holt 15 The gate bias voltage is chosen to be VGG = 4 V and the drain bias voltage is chosen to be VDD = 20 V. What is the largest value that can be used for RD to keep the transistor in the saturation region? Express your answer to three significant figures. ▸ View Available Hint(s) VDD UGS = 5.5 20 UDS (V)
In the following electrical circuit, a MOSFET transistor is operating in the saturation regime. VDD Vin R1 R2 R3 NMOS Vout 0 Derive an expression for the gain of this circuit.
A circuit is built around a bi-polar NPN transisor. The base network has a diode and a capacitor in series while the collector is connected to the power supply through a resistor. if the resistor is connected to ground; i) draw the circuit ii) provide all the masking layout of the circuit
Find for the given npn BJT circuit: IB, Ic, IE, VCB, B VBE = 0.7V VCC = 8V Rc 470 N 8 V 24 V 4.7 kl VBB 4 V Tamic Onio
Help. I am eager to learn to be a better student.
Of the circuit with the given BJT a) Calculate the values of VE1, VE2, VB1, VB2, IE1, IE2. b) Find the input and output impedance. c) Find the current gain. d) Find the voltage gain. VBE = 0.7 V, VD = 0.7 V, VCC = + 20V, β = 100 , R1 = R2 = 32k

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