1/13/23, 2:09 PMQuestion 15Not yet answeredMarked out of 5MENG420L-Fall 2022-2023 Final Exam slot 1In the linear heat conduction experiment, the cause of the difference in temperature gradients in the below graph is:100121016T8000.010.020.030.040.050.060.070.08Distance from T1 (m)Select one:O a. the air gap between T3 and T6 causes a higher conductivity than that of the brass barO b. the difference in materials between the upper part and the lower part of the unitOc. the difference in diameter between the upper part and the lower part of the unitO d. the heat loss from the whole insulation of the specimen

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Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)

8th Edition

ISBN:9781305387102

Author:Kreith, Frank; Manglik, Raj M.

Publisher:Kreith, Frank; Manglik, Raj M.

Chapter6: Forced Convection Over Exterior Surfaces

Section: Chapter Questions

Problem 6.25P

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Heat transfer Question Please explain how to write an excel spreadsheet that will calculate the temperature at any time and any location for a cylinder that is being cooled by convection using the first 4 terms of the Fourier expansion that is a solution to the PDE. Input variables are to be Tj, Too, h, k, p, D.t Try this over a variety of Fourier numbers, some less than .2, some near 0.2, and some much greater than 0.2
I do not understand how to read the graph to determine what ? is. Please help me read the graph to understand it. The temperature distribution in a flat slab needs to be studied under the conditions shown in the table. The ? in the table indicates insulated boundary and Q is the distributed heat source. In all cases assume the upper and lower boundaries are insulated. Assume that the units of length, energy, and temperature for the values shown are consistent with a unit value for the coefficient of thermal conductivity.
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The left side of this equation tells how much energy Q the cylinder gives to the water while it cools. The right side of this equation tells how much energy Q the water and aluminum cup absorb from the cylinder to warm up. Because it is the same energy, they are equal. What is known in this equation? Mcyl 411.7 g, malum 46.5 g, malum+water = 175 g Can you find: mwater =? g Twater = Talum = 20°C (water and cup of room temperature) 90°C, T; = 35°C (hot cylinder and cool "cylinder+cup+water" temperatures) Tcyl kCal Calum = 0.22, Cwater 1 (specific heat of water and aluminum, measured in units kg-°C What are we looking for is Ccul - How we find it? Plug all the numbers into the equation (1), Ccul will be one unknown which you can calculate from the equation. Important, convert all the masses from grams to kilograms! After you find Ccyl, compare it to known value for the copper 0.093(our cylinder is made out of copper). |Ceyl -0.093| % : · 100% 0.093
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1.77 Explain each in your own words. (a) What is the mode of heat transfer through a large steel plate that has its surfaces at specified temperatures? (b) What are the modes when the temperature on one surface of the steel plate is not specified, but the surface is exposed to a fluid at a specified temperature?
1.22 In order to prevent frostbite to skiers on chair lifts, the weather report at most ski areas gives both an air temperature and the wind-chill temperature. The air temperature is measured with a thermometer that is not affected by the wind. However, the rate of heat loss from the skier increases with wind velocity, and the wind-chill temperature is the temperature that would result in the same rate of heat loss in still air as occurs at the measured air temperature with the existing wind. Suppose that the inner temperature of a 3-mm-thick layer of skin with a thermal conductivity of 0.35 W/m K is and the air temperature is . Under calm ambient conditions the heat transfer coefficient at the outer skin surface is about (see Table 1.4), but in a 40-mph wind it increases to . (a) If frostbite occurs when the skin temperature drops to about , do you advise the skier to wear a face mask? (b) What is the skin temperature drop due to the wind?
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Completely solve and box the final answer. Write legibly. 3. An electrical wire with 0.4cm in diameter and 2.5m long extends across a room with 15deg C temperature. Heat is generated in the wire as a result of resistance heating, and the surface of the wire is measured to be 162degC. the voltage drop and electric current along the wire is 60V and 1.86 A, respectively. Determine the convection heat transfer coefficient for the heat transfer between the surface of the wire and the room air. Hint, electric power formula. Round your answer to 2 decimal places.
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