11. Chambers and coworkers have reported [NAD*] and [NADH] concentrations in yeast mitochondria as 20 mM and 0.3 mM, respectively. Consider the Malate Dehydrogenase reaction below: Malate + NAD* → Oxaloacetate + NADH + H* AG° = +29.7 kJ/mol If Malate concentration in yeast mitochondria is 0.4 mM what is the maximum concentration of oxaloacetate needed to make the reaction exergonic at pH 7.0 and 37°C?

Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
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Chapter1: Biochemistry: An Evolving Science
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**Question 11**

Chambers and coworkers have reported [NAD⁺] and [NADH] concentrations in yeast mitochondria as 20 mM and 0.3 mM, respectively. Consider the Malate Dehydrogenase reaction below:

\[ \text{Malate} + \text{NAD}^+ \rightarrow \text{Oxaloacetate} + \text{NADH} + \text{H}^+ \quad \Delta G'^{0} = +29.7 \, \text{kJ/mol} \]

If the Malate concentration in yeast mitochondria is 0.4 mM, what is the maximum concentration of oxaloacetate needed to make the reaction exergonic at pH 7.0 and 37°C?

- A. \(7.14 \times 10^{-5}\)
- B. \(2.04 \times 10^{-4}\)
- C. \(8.17 \times 10^{-6}\)
- D. \(5.45 \times 10^{-8}\)
- E. \(2.63 \times 10^{-7}\)
- F. \(4.69 \times 10^{-8}\)
- G. \(4.90 \times 10^{-7}\)
- H. \(3.13 \times 10^{-6}\)
- I. \(5.05 \times 10^{-6}\)
Transcribed Image Text:**Question 11** Chambers and coworkers have reported [NAD⁺] and [NADH] concentrations in yeast mitochondria as 20 mM and 0.3 mM, respectively. Consider the Malate Dehydrogenase reaction below: \[ \text{Malate} + \text{NAD}^+ \rightarrow \text{Oxaloacetate} + \text{NADH} + \text{H}^+ \quad \Delta G'^{0} = +29.7 \, \text{kJ/mol} \] If the Malate concentration in yeast mitochondria is 0.4 mM, what is the maximum concentration of oxaloacetate needed to make the reaction exergonic at pH 7.0 and 37°C? - A. \(7.14 \times 10^{-5}\) - B. \(2.04 \times 10^{-4}\) - C. \(8.17 \times 10^{-6}\) - D. \(5.45 \times 10^{-8}\) - E. \(2.63 \times 10^{-7}\) - F. \(4.69 \times 10^{-8}\) - G. \(4.90 \times 10^{-7}\) - H. \(3.13 \times 10^{-6}\) - I. \(5.05 \times 10^{-6}\)
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