11.A ring (side view shown in Figure Q11) has a circular solid cross-section of 5 mmdiameter. The ring itself has a radius of R = 100 mm and a very narrow gap at pointA, that allows the two free ends to be pulled apart by forces P, increasing the size ofthe gap.○PAFigure Q11Pa) Show that the total strain energy of the ring due to the applied forces is:U =3πP²R³2EI[12 marks]b) Find the maximum bending stress produced if forces of P = 8 N are applied.[6 marks]c) What minimum force P would cause the material in the ring to yield and atwhich locations could this yielding begin to occur?Useful informationE for the ring material = 75 GPaOyield for the ring material = 190 MPa[7 marks]

Answered: Image /qna-images/answer/b1ec70c1-3b77-43e5-86eb-a6d70a2c2d5d.jpg

Answered: 11. A ring (side view shown in Figure…

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter7: Analysis Of Stress And Strain

Section: Chapter Questions

Problem 7.6.13P: A solid spherical ball of magnesium alloy (E = 6.5 × l0-6 psi, v = 0.35) is lowered into the ocean...

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On the free surface of a component, a strain rosette was used to obtain the following normal strain data: €a = 300µɛ, ɛp = 400µs, and Ec = 200µe. Calculate the normal and shear strains in the x-y plane.
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