Answered: 100 lb ["₂ = 0.50 μ=0.40 P = 120 lb

Engineering

Mechanical Engineering

100 lb ["₂ = 0.50 μ=0.40 P = 120 lb

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

5. Force P = 120 lb is applied to the 100-lb block to maintain equilibrium against the wall.

[6] If θ = 15⁰, determine the friction force on the wall. (ANSWER: 46.346 lb)

[7] If θ = 30⁰, determine the normal force on the wall (ANSWER: 103.923 lb) and the friction force on the wall (ANSWER: 40 lb).

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