10.3. (a) Estimate the value of P/Paat for a sphere of radius 1 nm at 300 K if the surface tension is 1.6 J/m2and the atomic volume is 20×10-30 m3,Answer: P/PAat =5.2×10!() Calculate the relative change in average partial pressure at 1300 K as the average particle sizeincreases from 0.5 to 10 µm.Answer: Po.5um/P,0(c) Would your answer in part (b) have changed much if the final diameter of the particle were that ofa 10 cm3 sphere?Answer: Po.54m/P1ocm= 1.0068.10µm21.0072.

Answered: Image /qna-images/answer/1bf748e8-4337-4e23-8b3c-96bf5536031e.jpg

10.3. (a) Estimate the value of P/Plat for a sphere of radius 1 nm at 300 K if the surface tension is 1.6 J/m= and the atomic volume is 20×10-30 m³. Answer: P/Pfat = 5.2×106! (6) Calculate the relative change in average nartial

10.3. (a) Estimate the value of P/Plat for a sphere of radius 1 nm at 300 K if the surface tension is 1.6 J/m= and the atomic volume is 20×10-30 m³. Answer: P/Pfat = 5.2×106! (6) Calculate the relative change in average nartial

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Thermal Properties of Materials

In mechanical engineering, the thermal property is represented as the physical quantity that is relevant to the application of heat. The thermal properties are evaluated by variations in any specific material due to low heat or high heat. The quantities that influence the thermal property of the materials are mass, density, temperature, and many others.

Question

10.3. (a) Estimate the value of P/Paat for a sphere of radius 1 nm at 300 K if the surface tension is 1.6 J/m2
and the atomic volume is 20×10-30 m3,
Answer: P/PAat =5.2×10!
() Calculate the relative change in average partial pressure at 1300 K as the average particle size
increases from 0.5 to 10 µm.
Answer: Po.5um/P,0
(c) Would your answer in part (b) have changed much if the final diameter of the particle were that of
a 10 cm3 sphere?
Answer: Po.54m/P1ocm
= 1.0068.
10µm
21.0072.

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