Od 10.6x106O e. 10.60Clear my choiceion 7Calcium (Ca) has the Face-Centered Cubic (FCC) crystal structure. The edge length is a 0.548 nm.eteredWhat is the linear density In atoms/nm along direction [100j?ed out ofSelect one.onO a. 7.48Ob.4.00Oc3125O o.5.66Oe. 1824on 8Lihum L)hesme Booy-Centered Cuo c BCC aystalstucture shown in the figure below.Trerecus of re Lithumeromoreo15mreddout ofWhat is the olanar density in atoms/nmin elae (200Pianer My

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Answered: Od 10.6x106 O e. 10.60 Clear my choice…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

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11. A dislocation will dissociate into two partial dislocations if its energy is larger than the sum of energies of two partial dislocations. Based on this criterion show that in FCC a T01]dislocation can dissociate to two partial dislocations, namely Energy of dislocation can be approximated as: E z aGb?
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Rhodium has an FCC crystal structure; an atomic radius of 0.1345 nm and an atomic weight of 102.9 g/mol. Calculate the density of rhodium in grams per cubic centimeters a. 12.4 b. 6.20 c. 24.82 d. 9.30
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1. Many substances crystallize in a cubic structure. The unit cell for such crystals is a cube having an edge with a length equal to do. -Face diagonal a. What is the length, in terms of do, of the face diagonal, which runs diagonally across one face of the cube? (Hint: Use the Pythagorean theorem.) b. What is the length, again in terms of do. of the cube diagonal, which runs from one corner, through the center of the cube, to the opposite corner? (Hint: Make a right triangle having a face diagonal and an edge of the cube as its sides, with the hypotenuse equal to the cube diagonal, then use the Pythagorean theorem again.) 2. In an FCC structure, the centers of the atoms are found on the corners of the cubic unit cell and at the center of each face. The unit cell has an edge whose length is the distance from the center of one corner atom to the center of another corner atom on the same edge. The atoms on the diagonal of any face are touching. One of the faces of the unit cell is shown…
Au and Ag form a substitutional solid solution. This means that the crystal structure of an Au-Ag alloy consists of Ag atoms substituting for Au atoms in the regular atomic positions of the FCC structure. For an Au-50 wt% Ag alloy, what fraction of the atomic sites does Ni occupy? NA=6.022e23 A. None of the mentioned/ Geen van die genoemde B. 32.31% C. 50% D. 64.61%
5- Question 5. Some hypothetical alloy is composed of 42.5 wt% of metal A and 57.5 wt% of metal B. If the densities of metals A and B are 4.35 and 6.27 g/cm3, respectively, whereas their respective atomic weights are 91.4 and 105.3 g/mol, determine whether the crystal structure for this alloy is simple cubic, face-centered cubic, or body-centered cubic. Assume a unit cell edge length of 0.395 nm.
Calculate the number of vacancies per cubic meter in iron at 855°C. The energy of vacancy formation is 1.08 eV/atom. Futhermore, the density & atomic weight are 7.65g/cm3 & 55.85 g/mol respectively.
What can be determined when looking at the micostructure of this high manganease metal?
a) What is the difference between atomic structure and crystal structure? Explain with sketch. b) Based on atomic weights and structural information show that gold (FCC) and tungsten (BCC) essentially have the same density. (Agold = 197 amu/atom, Atungsten = 183.9 amu/atom, agold = 0.4079 nm, Atungsten = 0.3165 nm) i) Calculate the density of each. ii) Show that the atomic packing factor for BCC is 0.68

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