1. Write in the product of this reaction: HNO3, 0 H2504 CH2CH3 2. Write "most" under the compound which is most reactive toward electrophilic aromatic substitution (EAS). Write "least" under the compound which is least reactive toward that EAS. NO₂ OCH3 Br
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- As we will learn in Section 13.12, many antioxidants–compounds that prevent unwanted radical oxidation reactions from occurring–are phenols, compounds that contain an OH group bonded directly to a benzene ring. a. Explain why homolysis of the O–H bond in phenol requires considerably less energy than homolysis of the O–H bond in ethanol (362 kJ/mol vs. 438 kJ/mol). b.Why is the C–O bond in phenol shorter than the C–O bond in ethanol?What would be the effect on the rate of reaction if the concentration of the nucleophile weredoubled in an…a. SN1 reaction? Briefly explain.b. SN2 reaction? Briefly explain.Can you explain it? Provide examples with the various steps and explanations. How halogens affect the boiling/melting point? Does number of halogens affect it? For example, Ch3-Ch3 vs Ch3-Br vs Br-Ch3-Br
- 3. Nucleophilic aromatic substitution (NAS) reactions have the opposite trend in terms of reaction rate when compared with SN2 reaction rates. This is to say that aromatic fluorides undergo substitution the fastest under NAS conditions but the slowest under SN2 conditions. Using your knowledge of the mechanisms of these reactions, explain why this is the case. (Hint: It is important to consider the rate-determining step of each mechanism). NuO Nu Rate of reaction follows the following trend: F> CI > Br>1 NuO Nu Rate of reaction follows the following trend: I> Br > CI >F[References] Alkyl halides undergo nucleophilic substitution and elimination reactions. When the kinetics of the reaction are measured, if the rate of the reaction is found to be dependent only upon the concentration of the alkyl halide the reaction is first order. The substitution reaction is thus termed SN1, and the elimination reaction is termed E1. These reactions are unimolecular and occur in two steps. The first step is rate-limiting and involves the loss of the leaving group to form a carbocation. In the second, fast, step the nucleophile adds to the carbocation in the SN1 reaction or elimination occurs to give an alkene in the E1 reaction. Because the carbocation is planar, the nucleophile can add to either face and therefore racemization is usually observed although solvent effects can influence this somewhat. E1 elimination follows Zaitsev's rule and typically yields the most substituted alkene as the major product. Conditions which favor the SN1/E1 pathway include the use of…Please don't provide handwritten solution ..
- 1A. What is the trend for carbocation stability? 1B. In the reaction of 2-hexene with HBr, which of the products is expected to be formed in a larger amount. Explain your answer. 1C. Why do carbocation rearrangements occur?4. Write in the product, including stereochemistry where relevant, for these reactions. See end of ch. 8, p. 301-303. 1. BH3 AON 2. H₂O2, OH b) a) HBr -BrDraw structural formulas for the major organic product of the reagents shown
- The reaction shown proceeds via a single transition state with a trigonal bipyramidal geometry. C1 C2 Br: + H3C 0: Two curved arrows are required to indicate all of the bond-making and bond-breaking processes in this reaction. Where should one of the arrows be drawn, if CH3O is the nucleophile? from a Br LP to the O atom from C1 to the O atom from C2 to the O atom from the C-O bond to Br from an O LP to C1 from an O LP to C2CANNOT BE HAND-WRITTENOnly one of the chlorine atoms in the molecule, 3,4-dichloronitrobenzene, will undergo nucleophilic substitution. Indicate which position will react and provide the expected product for the given reaction using reaction intermediates (resonance structures).