1. Write in the product of this reaction:HNO3,0H2504CH2CH32. Write "most" under the compound which is most reactive toward electrophilicaromatic substitution (EAS).Write "least" under the compound which is least reactive toward that EAS.NO₂OCH3Br

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Answered: 1. Write in the product of this…

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

Chapter18: Aromaticity

Section: Chapter Questions

Problem 18CTQ

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Alkyl halides undergo elimination reactions to produce alkenes by the reacting with strong bases as shown in the following reaction (see image). In general, compounds where the halogen is axial (axial position) are much more reactive than those in which they are in the equatorial position. Taking the above into account: a. Which of the following compounds would give a faster elimination reaction: cis-1-bromo-2-tert-butylcyclohexane or trans-1-bromo-2-tert-butylcyclohexane? Draw the corresponding structures and clearly explain the choice.
As we will learn in Section 13.12, many antioxidants–compounds that prevent unwanted radical oxidation reactions from occurring–are phenols, compounds that contain an OH group bonded directly to a benzene ring. a. Explain why homolysis of the O–H bond in phenol requires considerably less energy than homolysis of the O–H bond in ethanol (362 kJ/mol vs. 438 kJ/mol). b.Why is the C–O bond in phenol shorter than the C–O bond in ethanol?
As we will learn in Section 15.12, many antioxidants-compounds that prevent unwanted radical oxidation reactions from occurring-are phenols, compounds that contain an OH group bonded directly to a benzene ring. a. Explain why homolysis of the O-H bond in phenol requires considerably less energy than homolysis of the O-H bond in ethanol (362 kJ/mol vs. 438 kJ/mol). b. Why is the C-O bond in phenol shorter than the C-O bond in ethanol? -O-H CH,CH2-0-H phenol ethanol
What would be the effect on the rate of reaction if the concentration of the nucleophile weredoubled in an…a. SN1 reaction? Briefly explain.b. SN2 reaction? Briefly explain.
4. The alkene below can be synthesized from two different alkyl bromides by an elimination reaction. One of the alkyl bromides gives only this alkene product, but the other one gives a mixture of alkene products. Provide the structures of the two possible starting alkyl bromides. Which will give the single alkene below?
Practice Problems Complete and balance each substitution reaction. 1. HOH + (CH3)3CI -> 2. CH3CH2CH3 + C2 Sunlight>
Answer number 19, 20, and 21.
How many moles of Bra are required to completely halogenate the alkene?A. One moleB. Two molesC. Three molesD. Four moles What is the expected arrangement of the bromine atoms relative to each other amongthe carbon involved in pi bonding?A. anti-conformationB. syn-conformationC. trans-configurationD. cis-configuration What happens to bromine when it is adjacent to an alkene during a chemical reaction?A. Bromine becomes stable. (? kasi before brown siya/acidic tas naging colorless? Jk ewan)B. Bromine becomes polarized.C. Bromine becomes hybridized.D. Bromine becomes acidic. The relative arrangement of bromine atoms in the product is primarily due to:A. ElectronegativityB. RepulsionC. Hydrogen bondingD. Atomic weightWhat is your observation after the reaction?A. A yellow flame is produced.B. Bromine water decolorizes.C. The alkene becomes denser.D. A brown precipitate forms.
4
In consideration of this class of rearrangements, the relationship between the cyclopropylcarbinyl and homoallyl cations is best described as.... Resonance structures, Conformational isomers, Stereoisomers, or None of these
Subject :- Chemistry
6. The addition reaction of unsymmetrical molecules, e.g. HCI, H20, to unsymmetrical alkene molecules, e.g. propene, produces two products: a main product and a byproduct. The main product is the one obtained according to Markovnikov's rule and the by-product is the one obtained not according to Markovnikov's rule. Complete the given equations of chemical reactions by writing the semi-structural formulas of the missing substrates and products. Circle the main products. A. 2CH, = CH- CH, – CH, + 2HCĮ- В. В. 2 +2H,0- + CH, — сH, — сн, - он

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1. Write in the product of this reaction: HNO3, 0 H2504 CH2CH3 2. Write "most" under the compound which is most reactive toward electrophilic aromatic substitution (EAS). Write "least" under the compound which is least reactive toward that EAS. NO₂ OCH3 Br