1. Values of Kw as a function of temperature are as follows: Temperature (°C) 0 25 35 40 50 Kw 1.14 x 10-15 1.00 x 10-14 2.09 x 10-14 2.29 x 10-14 5.47 x 10-14 a. Is the autoionization of water exothermic or endothermic? Only legible answers in the provided box will be considered. The autoronization of water is endothermic. As the temperature increases ko gets bigger, this means that the autolonization of water fowers products as temps. get higher. There's more H₂0+ present from the lonization of water at higher temps. Гон7 н.611 b. Calculate [H*] and [OH-] in a neutral solution at 50 °C H₂0 = H²(aq) +0H(aq) Ht

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1. Values of Kw as a function of temperature are as follows:
Temperature (°C)
0
25
35
40
50
Kw
1.14 x 10-15
1.00 x 10-14
2.09 x 10-14
2.29 x 10-14
5.47 x 10-14
a. Is the autoionization of water exothermic or endothermic? Only legible answers
in the provided box will be considered.
The autoronization of water
is endothermic. As the temperature
increases ko gets bigger, this means that the autolonization of water
fowers products as temps get higher. There's more H₂0+ present from the lonization
of water at higher temps.
Ku= [OH] [#₂0]
pott/ pH=7
b. Calculate [H*] and [OH-] in a neutral solution at 50 °C
+₂0 = H²(g) +0H(aq)
Transcribed Image Text:1. Values of Kw as a function of temperature are as follows: Temperature (°C) 0 25 35 40 50 Kw 1.14 x 10-15 1.00 x 10-14 2.09 x 10-14 2.29 x 10-14 5.47 x 10-14 a. Is the autoionization of water exothermic or endothermic? Only legible answers in the provided box will be considered. The autoronization of water is endothermic. As the temperature increases ko gets bigger, this means that the autolonization of water fowers products as temps get higher. There's more H₂0+ present from the lonization of water at higher temps. Ku= [OH] [#₂0] pott/ pH=7 b. Calculate [H*] and [OH-] in a neutral solution at 50 °C +₂0 = H²(g) +0H(aq)
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