**Problem: Calculating the [H₃O⁺] of an Aqueous Solution**Calculate the [H₃O⁺] of an aqueous solution of vinegar with [OH⁻] = 1.0 x 10⁻¹¹ M.**Given:** \[ K_w = [H₃O⁺][OH⁻] = 1.0 \times 10^{-14} \]**Options:**- A) 1.0 x 10⁻¹¹ M- B) 1.0 x 10⁻³ M- C) 1.0 x 10⁻²⁵ M- D) 1.0 x 10³ M**Explanation:**To find the concentration of hydronium ions \([H₃O⁺]\) in the solution, use the ion product constant of water \((K_w)\). The equation is:\[ K_w = [H₃O⁺][OH⁻] \]Rearranging for \([H₃O⁺]\):\[ [H₃O⁺] = \frac{K_w}{[OH⁻]} \]Substitute the given values:\[ [H₃O⁺] = \frac{1.0 \times 10^{-14}}{1.0 \times 10^{-11}} \]Calculation yields:\[ [H₃O⁺] = 1.0 \times 10^{-3} \, \text{M} \]**Correct Answer: B) 1.0 x 10⁻³ M**

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Answered: Calculate the [H3O+] of an aqueous…

Calculate the [H3O+] of an aqueous solution of vinegar with [OH-] = 1.0 x 10-11 M. Given: Kw = [H3O+][OH-] = 1.0 x 10-14 O 1.0 x 10-11 M 19 10...

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

**Problem: Calculating the [H₃O⁺] of an Aqueous Solution**

Calculate the [H₃O⁺] of an aqueous solution of vinegar with [OH⁻] = 1.0 x 10⁻¹¹ M.

**Given:**
\[ K_w = [H₃O⁺][OH⁻] = 1.0 \times 10^{-14} \]

**Options:**

- A) 1.0 x 10⁻¹¹ M
- B) 1.0 x 10⁻³ M
- C) 1.0 x 10⁻²⁵ M
- D) 1.0 x 10³ M

**Explanation:**

To find the concentration of hydronium ions \([H₃O⁺]\) in the solution, use the ion product constant of water \((K_w)\). The equation is:
\[ K_w = [H₃O⁺][OH⁻] \]

Rearranging for \([H₃O⁺]\):
\[ [H₃O⁺] = \frac{K_w}{[OH⁻]} \]

Substitute the given values:
\[ [H₃O⁺] = \frac{1.0 \times 10^{-14}}{1.0 \times 10^{-11}} \]

Calculation yields:
\[ [H₃O⁺] = 1.0 \times 10^{-3} \, \text{M} \]

**Correct Answer: B) 1.0 x 10⁻³ M**

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