1. The figure shows Beam Diagrams 23 in the CISC Handbook of Steel Construction. The left end is allowed to move freely in vertical direction, but rotation is prohibited (thus free but guided). (a) write the mathematic formulation (b) Find the deflection of the beam with a detailed derivation 23. BEAM FIXED AT ONE END, FREE BUT GUIDED AT OTHER - CONCENTRATED LOAD AT GUIDED END M Mmax Shear Moment 7/2 "max Equivalent Tabular Load. R=V. M max. (at both ends). Mx. A max. (at deflected end) Ax = 4P = P Pl 2 = P P13 12 El P (1-x)² (1+2x) 12 EI

1. The figure shows Beam Diagrams 23 in the CISC Handbook of Steel Construction. The left end is allowed to move freely in vertical direction, but rotation is prohibited (thus free but guided). (a) write the mathematic formulation (b) Find the deflection of the beam with a detailed derivation 23. BEAM FIXED AT ONE END, FREE BUT GUIDED AT OTHER - CONCENTRATED LOAD AT GUIDED END M Mmax Shear Moment 7/2 "max Equivalent Tabular Load. R=V. M max. (at both ends). Mx. A max. (at deflected end) Ax = 4P = P Pl 2 = P P13 12 El P (1-x)² (1+2x) 12 EI

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Q: problem

Concept explainers

Beams

In structural engineering, a beam is a component made of a variety of materials (including steel alloys, and wood) that can resist loads applied laterally to the beam axis. Members, elements, rafters, shafts, and purlins are all terms used to describe beams.

Question

1. The figure shows Beam Diagrams 23 in the CISC Handbook of Steel Construction. The left end is
allowed to move freely in vertical direction, but rotation is prohibited (thus free but guided).
(a) write the mathematic formulation
(b) Find the deflection of the beam with a detailed derivation
23. BEAM FIXED AT ONE END, FREE BUT GUIDED AT OTHER-CONCENTRATED LOAD
AT GUIDED END
M
Shear
Max
Moment
72
M.
R
max
Equivalent Tabular Load.
R=V
M max. (at both ends)
Mx.
A max. (at deflected end)
Ax
= 4P
= P
PL
2
= P(-1/2-x)
P13
12 El
P(1-x) ²
12 EI
-(1+2x)

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