1. The acid dissociation constant for HBRO is 2.8 x 109. Calculate the equilibrium concentrations of all substances if the initial concentration is 0.050 M for HBRO.
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![X = 2.4X10-4
2.8X10-9
) HB O = Br® +H'
Reachon
Hiap)
BrO cag)
Initial
o:050M
Change
Equilibrund 0-05o-X
0.050- X
Hosumphon
ha = CH*][BO]
[HBr0]
= 0.050 -X z 0.050
0-48% The percent is
less than 5% the
Assupassumphion is Valid
x²
0.050
H"=Br0]=x = 2-4X10
%3D
つ
HBro) -0-050 - 2 4X10-4
%3D
= (H+]e
CHAJ;
% di ssociahon
X 100%
=0.0498M
2 0·050 M
= 2-4X104M
X 100%
% =
O:050 M](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd86e2176-2b92-4a94-a128-f6a0aba0ae4d%2F1e00c662-9786-4265-ab3c-96978a41c9f0%2Feedo8y_processed.jpeg&w=3840&q=75)
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