1. Consider the temperature-composition 110°C). For a 80/20 mixture of toluene to benzene answer the following: Temperature (°C) 110 100 95 90 85 80 0.2 diagram shown below for benzene (bp = 80°C) and toluene (bp = 0.4 0.6 Mole Fraction of Toluene 0.8 1 a) At what temperature will the mixture begin to boil (use just approximate values)? b) When the mixture begins to boil, what is the mol % benzene in the vapor? c) What is the boiling point of the liquid formed by condensation of the vapor? 110 100 95 90 85 80

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1. Consider the temperature-composition diagram shown below for benzene (bp = 80°C) and toluene (bp =
110°C). For a 80/20 mixture of toluene to benzene answer the following:
Temperature (°C)
110
8
95
90
3
80
1
T
1
1
0.2
0.4
0.6
Mole Fraction of Toluene
a) At what temperature will the mixture begin to boil (use just approximate values)?
b) When the mixture begins to boil, what is the mol % benzene in the vapor?
c) What is the boiling point of the liquid formed by condensation of the vapor?
1
0.8
110
100
95
90
85
80
Transcribed Image Text:1. Consider the temperature-composition diagram shown below for benzene (bp = 80°C) and toluene (bp = 110°C). For a 80/20 mixture of toluene to benzene answer the following: Temperature (°C) 110 8 95 90 3 80 1 T 1 1 0.2 0.4 0.6 Mole Fraction of Toluene a) At what temperature will the mixture begin to boil (use just approximate values)? b) When the mixture begins to boil, what is the mol % benzene in the vapor? c) What is the boiling point of the liquid formed by condensation of the vapor? 1 0.8 110 100 95 90 85 80
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