Answers must be expressed in engineering notation (when the exponent of the base ten multiplier is not amultiple of 3, press ENG or SHIFT+ENG, whichever the case.)Example: 0.06N or 6.0x10² N must be expressed to 60x10-³N or 60mN1. Consider a beam of electrons that moves from the electron gun towards the screen of a cathode ray tubedue to the potential difference of 15kV. A pair of coils are placed outside a cathode ray tube and produce auniform magnetic field of 250 μT across the tube. Calculate the force experienced by the electrons if themagnetic field is in place:a. parallel with the direction of the beam.b.Perpendicular with the direction of the beam.c. 50 degrees with the direction of the beam.

Magnetic field The Magnetic force F→, experienced by the electron in the Magnetic field B is given…

Answered: 1. Consider a beam of electrons that…

Similar questions

1. A beam of electrons whose kinetic energy is Kemerges from a thin-foil "window" at the end of an accelerator tube. Ametal plate at distance d from this window is perpendicular to the direction of the emerging beam. What minimum strength uniform magnetic field could you apply to prevent the beam from hitting the metal plate? Express your final answer in terms of K, d, and any known constants.
A proton is going 28 m/s when it is exposed to a 3 T magnetic field (see below) and begins moving in a circle. Determine the direction of the magnetic force, the radius of the mass of 1.67×10-27 kg. Ignore gravity. motion, and the period (time to complete one orbit). A proton has a charge of 1.6x10-19 C & Direction of magnetic force: Choose direction ✓ ……..…….……………………………………..... Radius= Period = direction of velocity direction of external magnetic field
An electron moving in the negative x-direction (-i) through a uniform magnetic field pointing in the positive z-direction (+k) would experience a force in the... O a. positive y-direction (+j) b. negative y-direction (-) c. positive z-direction (+k) O d. negative z-direction (-k)
1. An alpha-particle (m = 6.64-10-27 kg; q = 3.2.10-19 C) travels in a circular path of radius 30 cm in a uniform magnetic field of magnitude 1.8 T. (a) What is the speed of the particle? m/s V= (b) What is the kinetic energy in electron-volts? KE= eV (c) Through what potential difference must the particle be accelerated in order to give it this kinetic energy? V= V Hint: What is the relationship between electric potential energy and electric potential? What is the relationship between the change in kinetic energy and the change in the potential energy of the alpha particle? 0
4. A particle charged with +40 µC moves with a velocity of 7 = 60 km/s k-80 km/s ĵ. It Use the B = 0.50 Ti enters the magnetic field of a particle detector, which is given by Lorentz' force equation to find the initial force on the particle. Remember, force is a vector.
A proton is traveling with velocity 4.3 × 106 m/s in a region containing a magnetic field of 0.33 T. The velocity of the proton is perpendicular to the magnetic field. a) Describe the trajectory of the proton (i.e., the shape of it in space). b) How many loops will the proton complete in 1 second? c) What would be the qualitative difference between the trajectory of a proton and the trajectory of an electron?
39
I... e... S... V... e... h... W... 9... W... O... U... a... of t... fiel... epa... smartermarks.com An unknown charged particle is travelling from the left and enters a perpendicular magnetic field as shown below. The magnetic force on the particle alters its path into a circular path of radius, r. * * * * * * * m S X X X Row 0 X * X I negative positive negative positive * X * * * * * * * Magnetic field into the page i ii X x X X 11. The sign of the charge must be force on this moving charge is The statement above is best completed by the answers in row: X and the direction of the magnetic 52 11 towards the bottom of the page out of the page towards the top of the page towards the top of the page Smarte 12. The particle has a mass of 4.68x10-27 kg and is travelling from the right at 8.00 x 106 If it's charge is 2.75 x 10-19 C and the perpendicular magnetic field is 7.75 mT calculate the radius of curvature of the circular path in meters. (Record your answer in the numerical-response…
An alpha particle (m = 6.68 x 1027 kg, q = +2 e.c.) is fired through a velocity selector that is created by an electric field of 4.5 x 105 N/C and a magnetic field of 0.90 T. It then enters a second magnetic field of 1.5 T. a) Explain how a velocity selector works and determine the speed which the alpha particle must have been moving at. b) After half a revolution in the second magnetic field, the alpha particle exits the field. How far from its point of entry does it leave?
8. An electron is moving through a magnetic field in a direction perpendicular to the field as shown below. The charge is moving with a speed of v = 3.5 × 105 and it experiences a force of F = - S 1.79 × 10-13 N. What is the magnitude and direction of the magnetic field? The charge of an electron is qe= = -1.6 × 10-19 C. v2 F
thanks!
4. A 50 turn, current carrying, flat square coil of wire contains an area of 1.000 cm2. It's magnetic moment has a magnitude of 2.400 mA m². a) Find the current in the coil. b)A 1.2T magnetic field makes an angle of 28° with respect to the normal to the coil. Find the torque on the coil.

SEE MORE QUESTIONS