8. An electron is moving through a magnetic field in a direction perpendicular to the field as shown below.The charge is moving with a speed of v = 3.5 × 105 and it experiences a force of F =-S1.79 × 10-13 N. What is the magnitude and direction of the magnetic field? The charge of an electronis qe= = -1.6 × 10-19 C.v2F

Given: Speed of electron v=3.5×105 m/s (rightward or positive x axis), Force F=1.79×10-13 N…

An electron is moving through a magnetic field in a direction perpendicular to the field as shown below. The charge is moving with a speed of = 3.5 × 105 and it experiences a force of F = m S 1.79 × 10-13 N. What is the magnitude and direction of the magnetic field? The charge of an electron is qe = -1.6 x 10-1⁹ C. v 1 F

An electron is moving through a magnetic field in a direction perpendicular to the field as shown below. The charge is moving with a speed of = 3.5 × 105 and it experiences a force of F = m S 1.79 × 10-13 N. What is the magnitude and direction of the magnetic field? The charge of an electron is qe = -1.6 x 10-1⁹ C. v 1 F

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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