6. A particle with a charge of q = 1.6 x 10-1º C and a mass of 1.39 x 10-25 kg enters a mass spectrometer with a velocity of 4.0 x 105 The particle strikes the detector 60 cm from where it entered the magnetic field. What is the strength of the magnetic field? 60 cm m 5 = 4.0 x 105 m = 1.39 × 10 kg

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Chapter1: Units, Trigonometry. And Vectors
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6. A particle with a charge of g = 1.6 x 10-19 C and a mass of 1.39 x 10-25 kg enters a mass
spectrometer with a velocity of 4.0 x 105 ™. The particle strikes the detector 60 cm from where it
entered the magnetic field. What is the strength of the magnetic field?
60 ст
v = 4.0 x 105
m = 1.39 x 10-25
kg
4.
O O O O
O O O O
O O O O.
O O/O O
O Q O O
O aO O
O OO O
O O O Q.
O O O O
O O O O
Transcribed Image Text:6. A particle with a charge of g = 1.6 x 10-19 C and a mass of 1.39 x 10-25 kg enters a mass spectrometer with a velocity of 4.0 x 105 ™. The particle strikes the detector 60 cm from where it entered the magnetic field. What is the strength of the magnetic field? 60 ст v = 4.0 x 105 m = 1.39 x 10-25 kg 4. O O O O O O O O O O O O. O O/O O O Q O O O aO O O OO O O O O Q. O O O O O O O O
Expert Solution
Step 1

Mass of particle (m) = 1.39×10-25 kg Charge of particle (q) = 1.6×10-19 C Velocity of particle (v) = 4×105 msDiameter of the circular path followed (d) = 60 cm Radius of the path followed (r)= 30 cm = 0.30 m 

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