A proton (always having a charge of 1.6 x 10 19 C)moves at (1.3x10^4) m/s through a magnetic field of (9.000x10^-3) T. What is the strength of the force acting on the proton? Answer in scientific notation, rounding your answer to two decimal places.

A proton (always having a charge of 1.6 x 10 19 C)moves at (1.3x10^4) m/s through a magnetic field of (9.000x10^-3) T. What is the strength of the force acting on the proton? Answer in scientific notation, rounding your answer to two decimal places.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: ulate the magnitude of magnetic field at a distance of (4.810x10^0) mm from a long straight wire…

Q: What is the radius of the path of an electron (mass 9 x 10-31 kg and charge 1.6 x 10¬1ºC ) moving at…

Q: A rival has created a device to scare off a teacher due to his noted fear of electrons. Around her…

Q: 23. An electron moves along the z axis with velocity v = c/ 10 in a region of the plane where there…

Q: A proton moves through a magnetic field at 25.7% of the speed of light. At one location, the field…

A: FB=3.918x10-14NExplanation:Step 1: Step 2: Step 3: Step 4:

Q: A proton moves through a magnetic field of magnitude 2 T at a speed of 5 x 106 m/s perpendicular to…

A: Given, Magnetic field=2T Speed=5×10^6m/s Angle=90 Centripetal acceleration=? Mass of…

Q: :A proton moves through a uniform magnetic field given by B = (30 î – 20ĵ) mT. At a time t1, the…

A: Given Data Uniform magnetic field is given as B→=(30.0 i^-20.0j^) mT=(30.0i^-20.0j^ )×10-3 T…

Q: 2: A wire of length L= 0.65 m and mass m = 0.095 kg carries a current of I= 0.75 A. The wire is…

Q: A particle with a charge -1.24X10^-8 C is moving with instantaneous velocity v=(4.19x10^4 m/s)i +…

Q: A particle with positive charge q = 3.68 x 10-18 C moves with a velocity v = (51 + 5ĵ- k) m/s…

Q: proton is entering a region of a uniform magnetic field of strength (3.600x10^-3) T. The proton…

Q: Q.3: An electron moves through a uniform magnetic field given by B = (B,î + 3.0Bzj)T. At a…

Q: Two electrons are fired into a particle accelerator. Their speed is equal at 112,664,134 m s¹, and…

A: The objective of the question is to find the difference in forces experienced by two electrons…

Q: A wire 2 m long has a mass of 342 g. The wire is connected to an emf. What is the minimum current in…

A: Write the given values with the suitable variables. L=2 mm=342 g=0.342 kgB=1.9 T Here, L, m, and B…

Q: 5. A particle of charge q = 0.200 C and mass m 2.00 kg is moving with instantaneous velocity v =…

Q: Q3- A charged particle having charge 4x1018 C and mass 20 g moves with a velocity of i = (î – 2j )…

A: Given: The charge on the particle is 4x10-18 C. The mass of the charged particle is 20 g.

Q: If a charge of magnitude 2.82x10-17C, with speed 1.4x106 m/s, and mass 2.01x10-25kg moves within the…

Q: A proton (with mass mp = 1.67 x 10-27 kg, charge qp = 1.6 x 10-19 C) moving with a speed of 0.80 x…

A: Ans:- Image-1

Q: Motion of Charged Particles in Magnetic Field A singly charged ion of 7Li (an isotope of Lithium)…

Q: Two long straight current-carrying wires both have currents of 131.2 T directed to the right. The…

A: The magnetic field at distance R due a current carrying conductor is given as B=μ0I2πRB1=4π×10-7…

Q: The mass of an ion can be determined by measuring its cyclotron frequency in a strong magnetic…

A: Formula:f=qB2πmRe-arranging the above equation we get, m=qB2πf-----(1)where, q=1.6×10-19 Cf=2.3×106…

Q: A charge is moving perpendicular to a magnetic field and experiences a force whose magnitude is 2.11…

Q: The magnetic force dFB on a infinitesimal segment of current I is dF, = 1 dī × B Where dL is the…

A: The magnetic force is given by the formuladFb=IdL×BHere, I is the current passing through the…

Q: An ion with a charge to mass ratio of 1.10×104 C/kg travels perpendicular to magnetic field…

A: Given data: Charge to mass ratio of ion, qm=1.10×104 C/kg Magnetic field, B=9×10-1 T=0.9 T Radius…

Q: An electron moving at 3.95 × 103 m/s in a 1.05 T magnetic field experiences a magnetic force of 1.4…

A: Given data: Velocity (v) = 3.95×103 m/s Magnetic field (B) = 1.05 T Magnetic force (F) = 1.4×10-16…

Q: A charge is moving perpendicular to a magnetic field and experiences a force whose magnitude is 1.33…

A: Given: q1=q2 v1 and B1 are perpandicularF1=1.33*10-3 N now, v2(=v1) and B2(=B1) making angle 26.9°we…

Q: A proton (of mass, m=1.67 x 102/kg) starts moving in a circular path of radius 5 cm when it enters…

Q: A charge is moving perpendicular to a magnetic field and experiences a force whose magnitude is 4.15…

A: We know that force on acharge particle moving with speed v in magnetic field is given by F=qvBsinθ…

Q: Calculate magnetic force when v=(0,−2,−2) m/s= (−2j−2k) m/s and B=(−4,0,4) T=(−4i+4k) T and the…

Q: particles (electrons or protons) are first accelerated by an electric field and then injected into a…

Q: The circular particle accelerator at CERN has a radius of about 4.24 km. The accelerator uses strong…

Q: At one instant, one electron that is moving through a uniform magnatic filed has velocity V= 40i +…

A: Given : Velocity of electron, V = 40 i + 35 j ( m/s) magnetic force experienced by electron, F =…

Q: A proton (with charge of 1.6 x 10^-19 C and mass of 1.7*10^-27 kg) traveling at a speed of…

A: Given Charge on proton q=1.6×10-19 C Mass of proton m=1.7×10-27 kg Speed of proton v=53045750 m/s…

Q: THE Mag" segine dFs = 1 dEx B Where di is the displacement vector of the infinitesimal current…

Q: Find the radius of a proton's orbit when it moves perpendicular to a magnetic field of 0.76 T with a…

Q: T electrical force between two uranium nuclei placed a distance of 1.81 x 10^-12 m apart from one…

A: Given data: Two uranium nuclei Distance (r) = 1.81×10-12 m Required: The electrical force

Q: A negative charge of q = -2.2 * 10-17 C and m = 2.3 * 10-26 kg enters a magnetic field B = 1.9 T…

Q: Use the following constants if necessary. Coulomb constant, k = 8.987 × 10º N · m² /C². Vacuum…

Q: . A particle with charge 2.34 x 10^-6 C moves at 8.64 x 10^6 m/s through a magnetic field of…

A: Charge, q = 2.34 x 10^-6 CSpeed, v = 8.64 x 10^6 m/sMagnetic field of strength, B = 2.97 T.The angle…

Q: A particle with positive charge g = 3.52 x 1o-18 c moves with a velocity v = (5î + 41 - k) m/s…

A: Solution: Given Values, charge (q)=3.52×10-18 CVelocity (v→)=5i^+4j^-k ^ m/sMagnetic field…

Q: Directions: Answer the following problem, write your answer with complete solution. A particle with…

A: Charge of the particle (q) = 5 × 10-6 C Velocity of the particle (v) = 3 × 106 m/s Magnetic field (…

Q: A charge of 1.2 C having an initial velocity of = 3.91+3.3 m/s enters a region with an electric…

Q: An electron encounters an E and B fields. B field is given by B = 0.1 j T. Electron experiences a…

Q: Calculate the magnitude of the force on an electron moving at (8.0x10^0)×106 m/s at an angle of…

A: Required : Force on electron

Q: Protons move perpendicular to a magnetic fiekd where B= 1.1 T. Their path is a circle. Calculate the…

Q: 7. A proton is moving through a magnetic field in a direction perpendicular to the field as shown…

Concept explainers

Magnetic Field Of Coaxial Cable

The word coaxial means same axis. So for a long straight cable to be coaxial, it must have concentric cylindrical shaped conductor around it. Coaxial cable (popularly called ‘coax’) has various applications ranging from current conductors to radiofrequency signal transmitters. This cable has lower emission losses and provides protection from electromagnetic interference which allows signals with less power to transmit over longer distances.For example, currents produced in the pickup of a stereo turntable generally travel to the amplifier through a coaxial cable.The self-inductance of a coaxial cable is another important characteristic, because it influences the propagation of electrical signals in the cable.

Question

A proton (always having a charge of 1.6 x 10
C)moves at (1.3x10^4) m/s through a
magnetic field of (9.000x10^-3) T.
19
What is the strength of the force acting on the
proton?
Answer in scientific notation, rounding your
answer to two decimal places.
Note: Your answer is assumed to be reduced to
the highest power possible.
Your Answer:
х10
Answer
units

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

Define the electric field of a single charge and the magnetic force acting on a moving electric charge using the definitions and formulas in the photos.
Problem 2: = A particle with charge +2.0 C moves through a uniform magnetic field. At one instant the velocity vector is v (2î+4ĵ + 6k) m/sec and the magnetic force on the particle is F = (41-20ĵ+ 12k) N. The x and y components of the magnetic field are equal (Bx = By). Thus, the magnetic field is given by B = B×î + B×ĵ + B₂k. What are B× and B₂? Answer: Bx = -3 T and B₂ = −4 T.
A positive charge traveling with a speed of 9,678 m/s enters the deflection chamber of a mass spectrometer. In the deflection, chamber exists a uniform magnetic field of 0.55 T. The charge undergoes a deflection with a radius of curvature that is 0.024 m. If the charge is 1.602 x 10-19 C, what is its mass in atomic mass units*?
Use the equation E=Fq E= Gravitational constant q= mass of the proton
The circular particle accelerator at CERN has a radius of about 2.24 km. The accelerator uses strong magnetic fields to steer charged particles in a circle, while electric fields give them more and more energy every time around. Suppose we're steering protons using magnetic fields of magnitude 8.22 T. What would be the magnitude of the momentum, p, of a proton under those conditions? You may assume that the magnetic field involved is perpendicular to the motion of the charges (that's the most efficient configuration).
A positive charge traveling with a speed of 8,600 m/s enters the deflection chamber of a mass spectrometer. In the deflection chamber exists a uniform magnetic field of 0.8 T. The charge undergoes a deflection with a radius of curvature that is 0.033m. If the charger is 1.502 x 10^-19 C, what is its mass in atomic mass units? 1 Amu = 1.66 x 10^-27 kg
Let's take the Earth's magnetic field BE = 1.70 x 10-4 T pointing north. A metal cable attached to a space station stretches radially outward by 2.65 km. What would be the potential difference ( V) that develops between the ends of the cable if it travels westbound around Earth at 5.2 km/s?
Q. 3: A proton moves through a uniform magnetic field given by B = (30 î – 205) mT. At a time t1, the proton has a velocity given by = the proton is FB (Vz î + (2000m/s)ĵ) and the magnetic force of (4 * 10-17N) k. At that instant, what is the velocity vx?
2.4: A proton moves through a uniform magnetic field given by B = (10 i- 203 – 30k) mT. At a time ti, the proton has a velocity given by v = (v, i + v, j + (2000m/s)k ) and the magnetic force on the proton is F, = (4 • 10-i7N) i + (2 • 10-17 N) j. At that instant, what are the (i) velocity v½ and (b) velocity vy? %3D
An electron in a magnetic field moves along a circle with a radius of 25.4 m with a speed that follows: v(t)=V0e−bt where b = 0.56 s-1and V0 = 170 m/s. I need to find the angular acceleration at t=3.7s, but I don't know how I'm supposed to get that becuase the formula that we have says that it is the second derivative of angular position, but when I calculate angular position all I get is 6.57516 radians. I don't understand how I'm supposed to take a derivative of that since it doesn't have any variables. I don't know if it is needed for this, but I already calculated the centripetal acceleration as 18.0446m/s^2
A proton is propelled at 4××1066 m/s perpendicular to a uniform magnetic field. 1)If it experiences a magnetic force of 4.8×10−13 N, what is the strength of the magnetic field? (Express your answer using two significant figures.)
A 3.5 mC charge moves with a speed of 10,000 m/s in a magnetic field of 0.5 T. How much force is exerted on the charge?