I...e...S...V...e...h...W...9...W...O...U...a...of t...fiel...epa...smartermarks.comAn unknown charged particle is travelling from the left and enters a perpendicularmagnetic field as shown below. The magnetic force on theparticle alters its path intoa circular path of radius, r.* * * * ** *mSXXXRow0X *XInegativepositivenegativepositive*X* * * * * * *Magnetic field into the pageiiiXxXX11. The sign of the charge must beforce on this moving charge isThe statement above is best completed by the answers in row:Xand the direction of the magnetic5211towards the bottom of the pageout of the pagetowards the top of the pagetowards the top of the pageSmarte12. The particle has a mass of 4.68x10-27 kg and is travelling from the right at 8.00 x106If it's charge is 2.75 x 10-19 C and the perpendicular magnetic field is 7.75mT calculate the radius of curvature of the circular path in meters.(Record your answer in the numerical-response section below.)Your answer:

In the above figure the charge is going towards right The magnetic field is into the page We have to…

I... e... S... V... J... h... 7. W... 9... W... O... U... 1... An unknown charged particle is travelling from the left and enters a perpendicular magnetic field as shown below. The magnetic force on the particle alters its path into a circular path of radius, r. V * * * * * * * X X X XX * * Row D 0 D * * * * * * * * * * * * * * Magnetic field into the page * * * * * * * ii * * * * X 11. The sign of the charge must be force on this moving charge is The statement above is best completed by the answers in row: ¡ and the direction of the magnetic Smarte 1 || negative towards the bottom of the page positive out of the page negative towards the top of the page positive towards the top of the page

I... e... S... V... J... h... 7. W... 9... W... O... U... 1... An unknown charged particle is travelling from the left and enters a perpendicular magnetic field as shown below. The magnetic force on the particle alters its path into a circular path of radius, r. V * * * * * * * X X X XX * * Row D 0 D * * * * * * * * * * * * * * Magnetic field into the page * * * * * * * ii * * * * X 11. The sign of the charge must be force on this moving charge is The statement above is best completed by the answers in row: ¡ and the direction of the magnetic Smarte 1 || negative towards the bottom of the page positive out of the page negative towards the top of the page positive towards the top of the page

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Magnetic Field Of Coaxial Cable

The word coaxial means same axis. So for a long straight cable to be coaxial, it must have concentric cylindrical shaped conductor around it. Coaxial cable (popularly called ‘coax’) has various applications ranging from current conductors to radiofrequency signal transmitters. This cable has lower emission losses and provides protection from electromagnetic interference which allows signals with less power to transmit over longer distances.For example, currents produced in the pickup of a stereo turntable generally travel to the amplifier through a coaxial cable.The self-inductance of a coaxial cable is another important characteristic, because it influences the propagation of electrical signals in the cable.

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9...
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smartermarks.com
An unknown charged particle is travelling from the left and enters a perpendicular
magnetic field as shown below. The magnetic force on the
particle alters its path into
a circular path of radius, r.
* * * * *
* *
m
S
X
X
X
Row
0
X *
X
I
negative
positive
negative
positive
*
X
* * * * * * *
Magnetic field into the page
i
ii
X
x
X
X
11. The sign of the charge must be
force on this moving charge is
The statement above is best completed by the answers in row:
X
and the direction of the magnetic
52
11
towards the bottom of the page
out of the page
towards the top of the page
towards the top of the page
Smarte
12. The particle has a mass of 4.68x10-27 kg and is travelling from the right at 8.00 x
106
If it's charge is 2.75 x 10-19 C and the perpendicular magnetic field is 7.75
mT calculate the radius of curvature of the circular path in meters.
(Record your answer in the numerical-response section below.)
Your answer:

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