Answered: electron Trajectory A Magnetic Field…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Similar questions

A proton, that is accelerated from rest through a potential of 55 kV enters the velocity filter, consisting of a parallel-plate capacitor and a magnetic field, shown below. What is the proton's speed? Take mp 1.67 × 10-27 kg and e = = 1.6 × 10-¹⁹ C. P = E The magnetic field, B = (x) B (x) The speed, v = The E-field between the plates is 2.2 × 105 N/C. What B-field is required so that the protons are not deflected? Units Select an answer ✓ X Units Select an answer ✓
An electron moves with a speed of 0.01 c through a magnetic field of 30 millliTesla.a. If the electron is moving from east to west, and the field is pointed due north, in what direction will theelectron be deflected?b. What is the force of the deflection?
Consider a long, horizontal Large Wire with current of 10 A running through it. We want to levitate a horizontal, thin, 0.50 m length of wire above it. If the thin wire has a mass of 10 grams, and a current of 300 mA, how far above the Large Wire will it hover (net force of zero) due to magnetic and gravitational forces? A. If the thin wire hovers above the Large Wire due to their magnetic fields, are their currents going the same direction, or opposite directions. Explain. B. Draw a diagram and label the directions of currents, and all other relevant quantities and vectors. C. Find the distance above the Large Wire the small thin wire will hover (net force of zero). D. Would your answers to parts A and C change if we wanted to find a distance below (rather than above) the Large Wire that the smaller thin wire could hover, due to their magnetic fields. Explain. Don't calculate any values but draw a new diagram and explain how this situation compares to the problem above.

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electron Trajectory A Magnetic Field (into the screen) | Trajectory B