13. An electron moving perpendicular to a uniform magnetic field of 0.44 T moves in a circle with a speed of 1.8 x 107 m/s. What is the radius of the circle? (e= 1.60 x 10-19 C, m electron = 9.11 × 10-31kg) A. 0.39 mm B. 0.23 mm C. 3.9 mm y 105 m/s enters a 0.60 T magnetic field from the left D. 1.5 mm
13. An electron moving perpendicular to a uniform magnetic field of 0.44 T moves in a circle with a speed of 1.8 x 107 m/s. What is the radius of the circle? (e= 1.60 x 10-19 C, m electron = 9.11 × 10-31kg) A. 0.39 mm B. 0.23 mm C. 3.9 mm y 105 m/s enters a 0.60 T magnetic field from the left D. 1.5 mm
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Problem 13:**
An electron moving perpendicular to a uniform magnetic field of 0.44 T moves in a circle with a speed of \(1.8 \times 10^7 \text{ m/s}\). What is the radius of the circle?
\((e = 1.60 \times 10^{-19} \text{ C}, \, m_{\text{electron}} = 9.11 \times 10^{-31} \text{ kg})\)
Options:
- A. 0.39 mm
- B. 0.23 mm
- C. 3.9 mm
- D. 1.5 mm
---
**Problem 14:**
An electron moving at a speed of \(4.8 \times 10^5 \text{ m/s}\) enters a 0.60 T magnetic field from the left, as shown below. Find the direction and the magnitude of the Magnetic Force on the electron.
\((e = 1.60 \times 10^{-19} \text{ C})\)
Diagram Explanation:
- The diagram shows a magnetic field indicated by "x" symbols, which represents the field going into the page, and the velocity \(v\) of the electron moving to the right.
Options:
- A. \(4.6 \times 10^{-14} \text{ N}\) Downward
- B. \(2.3 \times 10^{-13} \text{ N}\) Upward
- C. \(9.0 \times 10^{-14} \text{ N}\) Downward
- D. \(0.6 \times 10^{-14} \text{ N}\) Upward](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F24227ad7-0cee-4cb3-bf8f-36b2c099999b%2F6ff29540-4727-4a90-8554-035b444d9493%2Fvoh2lu5_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem 13:**
An electron moving perpendicular to a uniform magnetic field of 0.44 T moves in a circle with a speed of \(1.8 \times 10^7 \text{ m/s}\). What is the radius of the circle?
\((e = 1.60 \times 10^{-19} \text{ C}, \, m_{\text{electron}} = 9.11 \times 10^{-31} \text{ kg})\)
Options:
- A. 0.39 mm
- B. 0.23 mm
- C. 3.9 mm
- D. 1.5 mm
---
**Problem 14:**
An electron moving at a speed of \(4.8 \times 10^5 \text{ m/s}\) enters a 0.60 T magnetic field from the left, as shown below. Find the direction and the magnitude of the Magnetic Force on the electron.
\((e = 1.60 \times 10^{-19} \text{ C})\)
Diagram Explanation:
- The diagram shows a magnetic field indicated by "x" symbols, which represents the field going into the page, and the velocity \(v\) of the electron moving to the right.
Options:
- A. \(4.6 \times 10^{-14} \text{ N}\) Downward
- B. \(2.3 \times 10^{-13} \text{ N}\) Upward
- C. \(9.0 \times 10^{-14} \text{ N}\) Downward
- D. \(0.6 \times 10^{-14} \text{ N}\) Upward
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