2. An electron has a speed of 1.4 x 106 m/s. It travels through a 3.8 T magnetic field that is perpendicular to its velocity. An electric field is perpendicular to the B field and the velocity of the electron. The electron's velocity is constant. Find the magnitude of the electric field.
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- A beam of electrons with velocity vx = 5 x105 m/s is introduced into a uniform magnetic field Bz = 30 mTesla. An electric field Ey is applied perpendicular to both the initial velocity and the magnetic field. What value of electric field must be applied to leave the electron beam undeflected? Select one: a. 6.0 x 10-6 V/m b. 1.5 x 104 V/m c. 3.0 x 104 V/m d. 16.6 V/m-0.35 µC has a velocity of 2500000 m/s at 45° to the +x axis in the xz plane, with a positive x and z A charge q = component. There is a magnetic field of magnitude 0.06 T. a) If B is along the +zaxis, what is the force on the charge? N along the +y axis b) If the force on the charge is 2 x 10-3 N along +y axis, what is the direction of B? degrees from the +zaxis in the xz plane.Physics 6. A loop of area 0.250 m2 is in a uniform 0.020 0-T magnetic field. If the flux through the loop is 3.8310-3 T·m2, what angle does the normal to the plane of the loop make with the direction of the magnetic field?
- 9. A electron with charge -1.60 × 10-19 C and mass 9.11 × 10-31 kg is accelerated from rest through 14.20 kV. It then enters a uniform magnetic field of 7.50 x 10-4 T that is oriented perpendicular to its direction of motion. (a) What is the radius of the path the electron follows in the magnetic field? (b) How long does it take the electron to make one complete circle in the magnetic field?An electron moves through a uniform electric field E = (2.60î + 4.80ĵ) V/m and a uniform magnetic field B = 0.400 T.Determine the acceleration of the electron when it has a velocity v = 11.0î m/s.(Give each component in m/s2.) ax= m/s2 ay= m/s2 az= m/s24. Please refer again to the diagram. This time we have a charge of 3.86 x 10^-6 C moving at velocity 7.00 x 10^5 m/s through a magnetic field of strength 1.28 T and an electric field of strength 8.92 x 10^5 N/C. What is the magnitude of the total force on this charge? 0.02 N 0.01 N 0.03 N 0.03 N
- 1. A magnetic field has a magnitude of 1.50 × 10-³ T, and an electric field has a magnitude of 4.00 × 10³ N/C. Both fields -3 point in the same direction. A positive 2.5 µC charge moves at a speed of 2.50 × 106 m/s in a perpendicular to both fields. Determine the magnitude of the net force that acts on the charge. N ssfánection that is 0 ssf60 sf60 ss 50 ssf6 €60 ssf60 ssA charged particle moves through a velocity selector at constant velocity. The velocity selector is configured with "crossed" electric and magnetic fields of magnitude E = 1.50 x 104 N/C and B = 0.4 T. %3D Hint a. What is the velocity of the charged particle? Velocity of the charged particle is x 104 m/s. b. When the electric field is turned off, the charged particle travels in a circular path of radius 6 mm, as it travels through the magnetic field (still at B = 0.4 T). What is the mass-to-charge ratio of the particle? Hint for (b) Mass-to-charge ratio of the part is kg/C. (Use the "E" notation to enter your answer in scientific notation. For example, to enter 3.14 × 10´ 12".) - 12 enter "3.14E-99. A velocity selector consists of electric and magnetic w fields described by the expressions E Bi, with B = 15.0 mT. Find the value of E such that a 750-eV electron moving in the negative x direction is undeflected. = Ek and B = %3D %3D %3D