2. Particle 1 and particle 2 travel along the y-axis and enter a region of space that has a uniform 2 T magnetic field in the z direction as shown in the Figure. Both particles have the same charge, Q=0.1 C, and both have the same speed, v= 10 m/s. If the particles are a distance Ax=x2-x1 = 0.3 meters apart when they exit the region, what is the difference in their mass, AM = M2-M1 (in grams)? yaxis B-out x-axh

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**Problem Statement:**

Particle 1 and particle 2 travel along the y-axis and enter a region of space that has a uniform 2 T magnetic field in the z direction, as shown in the figure. Both particles have the same charge, \( Q = 0.1 \, \text{C} \), and both have the same speed, \( v = 10 \, \text{m/s} \). If the particles are a distance \( \Delta x = x_2 - x_1 = 0.3 \) meters apart when they exit the region, what is the difference in their mass, \( \Delta M = M2 - M1 \) (in grams)?

**Diagram Explanation:**

- **Axes:** The diagram shows particles moving along the y-axis. After entering the magnetic field region, they are deflected, moving in a circular arc.
- **Magnetic Field:** The magnetic field is represented by dots, indicating that it is directed out of the page (B-out).
- **Particle Path:** The path of the particles is shown as arcs with radius \( R \), indicating circular motion due to the magnetic field.
- **Delta x:** The separation distance upon exiting, labeled as \( \Delta x \), is given as 0.3 meters.
- **Velocity (v):** Initial particle velocity is along the y-axis, indicated by \( v \). 

This scenario involves determining the mass difference between two charged particles after being subjected to a magnetic field. The mass affects the radius of the curvature of their path in the magnetic field, leading to differing exit points along the x-axis.
Transcribed Image Text:**Problem Statement:** Particle 1 and particle 2 travel along the y-axis and enter a region of space that has a uniform 2 T magnetic field in the z direction, as shown in the figure. Both particles have the same charge, \( Q = 0.1 \, \text{C} \), and both have the same speed, \( v = 10 \, \text{m/s} \). If the particles are a distance \( \Delta x = x_2 - x_1 = 0.3 \) meters apart when they exit the region, what is the difference in their mass, \( \Delta M = M2 - M1 \) (in grams)? **Diagram Explanation:** - **Axes:** The diagram shows particles moving along the y-axis. After entering the magnetic field region, they are deflected, moving in a circular arc. - **Magnetic Field:** The magnetic field is represented by dots, indicating that it is directed out of the page (B-out). - **Particle Path:** The path of the particles is shown as arcs with radius \( R \), indicating circular motion due to the magnetic field. - **Delta x:** The separation distance upon exiting, labeled as \( \Delta x \), is given as 0.3 meters. - **Velocity (v):** Initial particle velocity is along the y-axis, indicated by \( v \). This scenario involves determining the mass difference between two charged particles after being subjected to a magnetic field. The mass affects the radius of the curvature of their path in the magnetic field, leading to differing exit points along the x-axis.
Expert Solution
Step 1

Whenever any charged particle enter inside a uniform magnetic field and it's direction is perpendicular to the applied magnetic field then charge particle move in a circular path and radius of this circular path is given as

R = MV/QB

Here M is the mass of charge particle

V is the speed 

Q is the charge on particle

B is the magnitude of magnetic field 

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