A carbon-14 ion with a charge of +6.408x10^-19 C and a mass of 2.34x10^-26 kg is sent through a mass spectrometer and hits a detector at a point 10.0 cm to the left of where the beam leaves the velocity selector. The velocity selector and the detector are both in a region of magnetic field of strength 0.500 T. What are the magnitude and direction of the electric field in the velocity selector where the particles travel in a straight line for 15.0 cm?

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Chapter1: Units, Trigonometry. And Vectors
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A carbon-14 ion with a charge of +6.408x10^-19 C and a mass of 2.34x10^-26 kg is sent through a mass spectrometer and hits a detector at a point 10.0 cm to the left of where the beam leaves the velocity selector. The velocity selector and the detector are both in a region of magnetic field of strength 0.500 T.

What are the magnitude and direction of the electric field in the velocity selector where the particles travel in a straight line for 15.0 cm?

Please also explain and show the steps you used to get there/the physics behind why/how you got to the answer to help me better understand. Thank you soo much. Also, the work and the explanation or most important because I already have the correct answer - I'm just unsure of how to get there.

Region of
uniform
Particle
path
magnetic field
10.0 cm
Accelerating
plates
B
detector
15.0 cm
Transcribed Image Text:Region of uniform Particle path magnetic field 10.0 cm Accelerating plates B detector 15.0 cm
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