1. Compound M (C3H100) readily decolorizes Br2 in CCl4 and is converted to compound N (CsH120) by H2/Ni. The 'H NMR spectrum for M is shown below. The 13C NMR spectrum of M has signals at 146.1, 110.8, 71, and 29.4. Deduce the structures of M and N. Cs Hioo Gamp M Ce Su

1. Compound M (C3H100) readily decolorizes Br2 in CCl4 and is converted to compound N (CsH120) by H2/Ni. The 'H NMR spectrum for M is shown below. The 13C NMR spectrum of M has signals at 146.1, 110.8, 71, and 29.4. Deduce the structures of M and N. Cs Hioo Gamp M Ce Su

Organic Chemistry

9th Edition

ISBN:9781305080485

Author:John E. McMurry

Publisher:John E. McMurry

Chapter24: Amines And Heterocycles

Section24.SE: Something Extra

Problem 65AP: Phenacetin, a substance formerly used in over-the-counter headache remedies, has the formula...

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Concept explainers

NMR Spectroscopy

NMR stands for Nuclear Magnetic Resonance in which the study of different molecules is done based on the interaction of radiofrequency electromagnetic radiations with the nuclei of molecules placed in a strong magnetic field. A precise study of spectra of visible light and all bands of electromagnetic radiation is called spectroscopy.

Question

C. NMR Problems
1. Compound M (CSH100) readily decolorizes Br2 in CCI4 and is converted to compound
N (C;H120) by H2/Ni. The 'H NMR spectrum for M is shown below. The 13C NMR
spectrum of M has signals at 146.1, 110.8, 71, and 29.4. Deduce the structures of M
and N.
Cs Hioo
CampM
Checa Su

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