1. Compound M (C3H100) readily decolorizes Br2 in CCl4 and is converted to compound N (CsH120) by H2/Ni. The 'H NMR spectrum for M is shown below. The 13C NMR spectrum of M has signals at 146.1, 110.8, 71, and 29.4. Deduce the structures of M and N. Cs Hioo Gamp M Ce Su

1. Compound M (C3H100) readily decolorizes Br2 in CCl4 and is converted to compound N (CsH120) by H2/Ni. The 'H NMR spectrum for M is shown below. The 13C NMR spectrum of M has signals at 146.1, 110.8, 71, and 29.4. Deduce the structures of M and N. Cs Hioo Gamp M Ce Su

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

NMR Spectroscopy

NMR stands for Nuclear Magnetic Resonance in which the study of different molecules is done based on the interaction of radiofrequency electromagnetic radiations with the nuclei of molecules placed in a strong magnetic field. A precise study of spectra of visible light and all bands of electromagnetic radiation is called spectroscopy.

Question

C. NMR Problems
1. Compound M (CSH100) readily decolorizes Br2 in CCI4 and is converted to compound
N (C;H120) by H2/Ni. The 'H NMR spectrum for M is shown below. The 13C NMR
spectrum of M has signals at 146.1, 110.8, 71, and 29.4. Deduce the structures of M
and N.
Cs Hioo
CampM
Checa Su

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