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+ 1 R= 10kΩ + R+= 10kΩ X D RL Vo 2. Assume R₁-10K, C=0.1uF, and the diode cut-in voltage is 0.7V. Also assume that when the op-amp goes open-loop due to lack of negative feedback, Vx will be +12V when Vp>Vn and -12V when Vp

+ 1 R= 10kΩ + R+= 10kΩ X D RL Vo 2. Assume R₁-10K, C=0.1uF, and the diode cut-in voltage is 0.7V. Also assume that when the op-amp goes open-loop due to lack of negative feedback, Vx will be +12V when Vp>Vn and -12V when Vp

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Please answer both subproblems. Thank you.

+ Vin I V Vp R= 10kΩ R+= 10kΩ ww D C- RL Vo 2. Assume R₁-10K, C=0.1uF, and the diode cut-in voltage is 0.7V. Also assume that when the op-amp goes open-loop due to lack of negative feedback, Vx will be +12V when Vp>Vn and -12V when Vp<Vn. a. Suppose the capacitor is uncharged at t<0 and Vin becomes 10V from t = 0 to 0.1ms. Determine the state of the diode. Determine an expression for and sketch vo(t) and vx(t). Verify your assumption on the state of the diode. b. b. Following from (a), Vin now becomes -10V from t = 0.1ms to t=0.2ms. Repeat the analysis from (a)
Transcribed Image Text:+ Vin I V Vp R= 10kΩ R+= 10kΩ ww D C- RL Vo 2. Assume R₁-10K, C=0.1uF, and the diode cut-in voltage is 0.7V. Also assume that when the op-amp goes open-loop due to lack of negative feedback, Vx will be +12V when Vp>Vn and -12V when Vp<Vn. a. Suppose the capacitor is uncharged at t<0 and Vin becomes 10V from t = 0 to 0.1ms. Determine the state of the diode. Determine an expression for and sketch vo(t) and vx(t). Verify your assumption on the state of the diode. b. b. Following from (a), Vin now becomes -10V from t = 0.1ms to t=0.2ms. Repeat the analysis from (a)
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