*16. For the transistor configuration of Fig. 8.108: a. Solve for the currents IB, Ic, and I using the fact that VBE = 0.7 V and VCE = 8 V. b. Find the voltages VB, Vc, and VE with respect to ground. c. What is the ratio of output current Ic to input current IB? [Note: In transistor analysis this ratio is referred to as the dc beta of the transistor (Bac).] Vcc RB www 270 ΚΩ 20 V B 0.7 V RE Ic C + 8 V E E • 510 Ω FIG. 8.108 Problem 16. Rc www 2.2 ΚΩ Vcc 20 V

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BJT (Bipolar Junction Transistor)

A BJT is a semiconductor device with 3 terminals that consist of a p-n junction diode that can amplify the signal or current. It is a current-controlled device. The three BJT terminals are base, collector, and emitter. The BJT works with the charge carrier, the two type of carriers in the BJT are holes and electrons, the charge carriers flow by the process of recombination. The signal to be amplifier is generally given as the input at the base terminal and an amplified form of it is available at the collector terminal.