8. The sum of 2B and 6D in hex is equal to: A. 8C B. 7D C. 7C D. 6D E. 98 B.X+0=X 9. What statement is wrong? A. X+X´=1 X*1=X С. D. X*X'=0 E.X*X=1 10. Simplification of the function F(A,B,C,D) according to the map is: A. B'D+B'C'+A'CD´ B. B'D+B°C'+A°CD C. B'D'+B’C+A 'CD D. B'D+B'C'+A'C'D´ E. B'D'+B'C+A'CD´ 11. Positive-logic NOR gate is the same as negative-logic gate. A. OR B. NAND 12. Voltages V, V3, V4 in the scheme below equal to respectively. C. AND D. XOR E. XNOR +5V D V3 V1 10x2 A. 4.3 V, 0, 0 B. 0, 4.3V, 0 C. 4.3 V, 4.3 V, 0 D. 0 13. If we want to have 4*16 decoder we may construct it with: A. multiplexer and 3*8 decoder inverter C. three 2*4 decoders and 2 inverters B. two 2*4 decoders and D. two 3*8 decoders and inverter E. two 2*4 decoders and two 3*8 decoders

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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8. The sum of 2B and 6D in hex is equal to: A. 8C B. 7D C. 7C
D. 6D E. 98
9. What statement is wrong? A. X+X'=1
X*1=X
B.X+0=X
С.
D. X*X'=0 E.X*X=1
10. Simplification of the function F(A,B,C,D) according to the map
is:
A. B'D+B°C+A'CD'
В. В D+B'C'+А'CD
C. B’D’+B’C+A
'CD
D. B'D+B'C'+A'C'D'
E. B'D'+B'C+A'CD´
11. Positive-logic NOR gate is the same as negative-logic .
gate.
A. OR B. NAND
12. Voltages V,, V3, V4 in the scheme below equal to
respectively.
C. AND
D. XOR
E. XNOR
+5V
+5V
D3
V3
V1
10K2
10KQ
А. 4.3 V, 0, 0 В. О, 4.3V, 0 С. 4.3 V, 4.3 V, 0 D.0
13. If we want to have 4*16 decoder we may construct it with:
A. multiplexer and 3*8 decoder
inverter
C. three 2*4 decoders and 2 inverters
B. two 2*4 decoders and
D. two 3*8 decoders and
inverter
E. two 2*4 decoders and two 3*8 decoders
Transcribed Image Text:8. The sum of 2B and 6D in hex is equal to: A. 8C B. 7D C. 7C D. 6D E. 98 9. What statement is wrong? A. X+X'=1 X*1=X B.X+0=X С. D. X*X'=0 E.X*X=1 10. Simplification of the function F(A,B,C,D) according to the map is: A. B'D+B°C+A'CD' В. В D+B'C'+А'CD C. B’D’+B’C+A 'CD D. B'D+B'C'+A'C'D' E. B'D'+B'C+A'CD´ 11. Positive-logic NOR gate is the same as negative-logic . gate. A. OR B. NAND 12. Voltages V,, V3, V4 in the scheme below equal to respectively. C. AND D. XOR E. XNOR +5V +5V D3 V3 V1 10K2 10KQ А. 4.3 V, 0, 0 В. О, 4.3V, 0 С. 4.3 V, 4.3 V, 0 D.0 13. If we want to have 4*16 decoder we may construct it with: A. multiplexer and 3*8 decoder inverter C. three 2*4 decoders and 2 inverters B. two 2*4 decoders and D. two 3*8 decoders and inverter E. two 2*4 decoders and two 3*8 decoders
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