Homework Help is Here – Start Your Trial Now!
Engineering
Electrical Engineering
Problem 2: Thevenin's equivalent circuit 2502 3002 4002 5000 20V 3002 10V 2000 °B

Problem 2: Thevenin's equivalent circuit 2502 3002 4002 5000 20V 3002 10V 2000 °B

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
See similar textbooks
icon
Related questions
Question
Please answer all parts please. Thank you so much
Problem 2: Thevenin's equivalent circuit 2502 3002 $4002 5002 20V 23002 O 10V B Thevenin's equivalent resistance: Step 1- Short circuit all the voltage sources. This means that wherever there is a voltage source in the circuit you can replace it with a wire. Step 2-Open circuit all the current sources meaning that wherever there is a current source replace it with a blank (no connection). In above circuit, 300 250 A 400 500 300 200 300 400 4 500 300 B 200 Now, we can solve the resistor arrangement. Identify the series resistors and add them. 300 400 + 250 = 650 500 300 + 200 = 500 Short circuit In the above circuit, the series combination of 300 ohm and 200 ohm resistor is connected to a wire at both its terminals. Thus, if a current arrives at the junction, it is always going to take the path with the least resistance. Since the wire has zero resistance ideally, no current would flow cross the highlighted 500 ohm resistor. Therefore, we can disregard this resistor in our calculation. 300 650 500 650 || 500 B Finally, the Thevenin equivalent resistance Rth is given by [(650||500) + 300].
Transcribed Image Text:Problem 2: Thevenin's equivalent circuit 2502 3002 $4002 5002 20V 23002 O 10V B Thevenin's equivalent resistance: Step 1- Short circuit all the voltage sources. This means that wherever there is a voltage source in the circuit you can replace it with a wire. Step 2-Open circuit all the current sources meaning that wherever there is a current source replace it with a blank (no connection). In above circuit, 300 250 A 400 500 300 200 300 400 4 500 300 B 200 Now, we can solve the resistor arrangement. Identify the series resistors and add them. 300 400 + 250 = 650 500 300 + 200 = 500 Short circuit In the above circuit, the series combination of 300 ohm and 200 ohm resistor is connected to a wire at both its terminals. Thus, if a current arrives at the junction, it is always going to take the path with the least resistance. Since the wire has zero resistance ideally, no current would flow cross the highlighted 500 ohm resistor. Therefore, we can disregard this resistor in our calculation. 300 650 500 650 || 500 B Finally, the Thevenin equivalent resistance Rth is given by [(650||500) + 300].
Thevenin's equivalent voltage Vth: 2502 3002 A1 in 4002 5002 20V C 3002 10V 2002 B1 Since the 300 ohm resistor is open at one end, no current flows through it. Thus, the voltage at A and B is the same as A1 and B1. Voltage between A1 and B1 = (Voltage between A1 and C) + (Voltage between C and B1). The Voltage between C and B1 is 10V as it is directly connected to a 10V source. Apply mesh law in loop with i to find voltage across 500 ohm resistor. Vs00 = 500 * i1 Substitute values in highlighted equation to find Vth across A and B.
Transcribed Image Text:Thevenin's equivalent voltage Vth: 2502 3002 A1 in 4002 5002 20V C 3002 10V 2002 B1 Since the 300 ohm resistor is open at one end, no current flows through it. Thus, the voltage at A and B is the same as A1 and B1. Voltage between A1 and B1 = (Voltage between A1 and C) + (Voltage between C and B1). The Voltage between C and B1 is 10V as it is directly connected to a 10V source. Apply mesh law in loop with i to find voltage across 500 ohm resistor. Vs00 = 500 * i1 Substitute values in highlighted equation to find Vth across A and B.
Expert Solution
steps

Step by step

Solved in 3 steps with 2 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Recommended textbooks for you
Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
Electrical Engineering
ISBN:
9780133923605
Author:
Robert L. Boylestad
Publisher:
PEARSON
Delmar's Standard Textbook Of Electricity
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:
9781337900348
Author:
Stephen L. Herman
Publisher:
Cengage Learning
Programmable Logic Controllers
Programmable Logic Controllers
Electrical Engineering
ISBN:
9780073373843
Author:
Frank D. Petruzella
Publisher:
McGraw-Hill Education
Fundamentals of Electric Circuits
Fundamentals of Electric Circuits
Electrical Engineering
ISBN:
9780078028229
Author:
Charles K Alexander, Matthew Sadiku
Publisher:
McGraw-Hill Education
Electric Circuits. (11th Edition)
Electric Circuits. (11th Edition)
Electrical Engineering
ISBN:
9780134746968
Author:
James W. Nilsson, Susan Riedel
Publisher:
PEARSON
Engineering Electromagnetics
Engineering Electromagnetics
Electrical Engineering
ISBN:
9780078028151
Author:
Hayt, William H. (william Hart), Jr, BUCK, John A.
Publisher:
Mcgraw-hill Education,
SEE MORE TEXTBOOKS