QUESTION 4 Convert the following to their phasor equivalent values type "cis" instead of the symbol "Z" e.g. 200cis(30deg) a) v(t) = 100 sin 1000t V= b) i(t) = 0.471 sin (1000t + 450° ) A= c) v(t) = 300 sin 500t = | d) i(t) = 5.2 sin (500t + 300°) A=
QUESTION 4 Convert the following to their phasor equivalent values type "cis" instead of the symbol "Z" e.g. 200cis(30deg) a) v(t) = 100 sin 1000t V= b) i(t) = 0.471 sin (1000t + 450° ) A= c) v(t) = 300 sin 500t = | d) i(t) = 5.2 sin (500t + 300°) A=
Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter2: Fundamentals
Section: Chapter Questions
Problem 2.2P: Convert the following instantaneous currents to phasors, using cos(t) as the reference. Give your...
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![QUESTION 4
Convert the following to their phasor equivalent values type "cis" instead of the symbol "z" e.g. 200cis(30deg)
a) v(t) = 100 sin 1000t V=
b) i(t) = 0.471 sin (1000t + 450° ) A=
c) v(t) = 300 sin 500t =
d) i(t) = 5.2 sin (500t + 300°) A=](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe8ffb8aa-1a66-4f53-a309-ce83630daeb4%2Fa9ff6b48-a07f-4907-bf55-fc5c4239122a%2Fxf0ylba_processed.png&w=3840&q=75)
Transcribed Image Text:QUESTION 4
Convert the following to their phasor equivalent values type "cis" instead of the symbol "z" e.g. 200cis(30deg)
a) v(t) = 100 sin 1000t V=
b) i(t) = 0.471 sin (1000t + 450° ) A=
c) v(t) = 300 sin 500t =
d) i(t) = 5.2 sin (500t + 300°) A=
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