10.3-What's the value of FS against overturning andsliding for the Figure shown.3Y = 18.08 kN/mC = 0kN23.58-m3 k = k,2Given: Yc; P, = 0%3Dp = 36°6.5m41.5m0.8m-0.8m ---0.6-2mY = 19.65 kN/mC = 30 kN/m?p = 15°

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-0.3 What's the value of FS against overturning and 3 sliding for the Figure shown. Y = 18.08 kN/m C = 0 kN = 23.58 ; P, = 0 Given: Yc p = 36° %3D m3i k = k2 6.5m 1.5m 0.8m 3 0.8m-0.6- 2m Y = 19.65 kN/m C = 30 kN/m? P = 15°

-0.3 What's the value of FS against overturning and 3 sliding for the Figure shown. Y = 18.08 kN/m C = 0 kN = 23.58 ; P, = 0 Given: Yc p = 36° %3D m3i k = k2 6.5m 1.5m 0.8m 3 0.8m-0.6- 2m Y = 19.65 kN/m C = 30 kN/m? P = 15°

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Beams

In structural engineering, a beam is a component made of a variety of materials (including steel alloys, and wood) that can resist loads applied laterally to the beam axis. Members, elements, rafters, shafts, and purlins are all terms used to describe beams.

Question

10.3-
What's the value of FS against overturning and
sliding for the Figure shown.
3
Y = 18.08 kN/m
C = 0
kN
23.58-
m3 k = k,
2
Given: Yc
; P, = 0
%3D
p = 36°
6.5m
4
1.5m
0.8m
-0.8m ---0.6-
2m
Y = 19.65 kN/m
C = 30 kN/m?
p = 15°

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