41. Determine the collapse load factor a for the propped cantilever = beam ABCD shown in Figure P4.1. Mp are constants. 80 kNm; E, I, and A 10a kN 20α kN 18 to B C 5m +2.5m/2.5m| FIGURE P4.1. Problem 4.1.

Q: P8.1. For the truss in Figure P8.1, compute the horizontal and vertical components of displacement…

A: Draw free body diagram of truss The joint C in the truss is considered for analysis by using the…

Q: 2) If the beam is subjected to a shear of V = 15 kN, determine the web's shear stress at A and B.…

A: Given : V = 15 kN Location of Neutral axis = 0.1747 m from the bottom INA = 0.2182 X 10-3 m4 This…

Q: 1.13 Determine the mass of the heaviest uniform cylinder that can be supported in the position shown…

A: t D there wil be Normal force Nθ NweightN cosθ = weight (w)N = wcos θcos θ = 610

Q: P8.3. For the truss in Figure P8.3, compute the horizon- tal and vertical components of the…

A: Draw free body diagram Consider the summation of forces in the horizontal direction…

Q: (a) Compute the vertical displacement of the hinge at C in Figure P8.34. EI is constant for all…

A: (a) Consider the free body diagram; To compute the vertical deflection at the support C, Assume…

Q: For the truss in Figure P8.3, compute the horizon-tal and vertical components of the displacement of…

A: Draw free body diagram Consider the summation of forces in the horizontal direction…

Q: P5.8 A steel [E = 200 GPa] bar (1) supports beam AB, as shown in Figure P5.8. The cross-sectional…

A:

Q: 1.38 The right-angle bar is supported by a pin at B and a roller at C. What is the maximum safe…

A: As per authoring guidelines, if the question number is not specified, the first question or three…

Q: 24 kN/m 250 mm 200 mm 1.75 m Fig. 2: Viga simple AB de madera

A:

Q: The C200×20 channel section of Figure P4.5 has second moments of area Ix = 15×10^6 mm4,…

A:

Q: Answer I. Use W=1290KN/m

A: Hi! Thank you for the question As per the honor code, We’ll answer the first question since the…

Q: 6.4. Figure P6.4 shows the cross section of a thin-walled beam subjected to a vertical shear force…

A:

Q: W=1290KN/m. Answer I.

A: Hi! Thank you for the question As per the honor code, We’ll answer the First question since the…

Q: Use Virtual Work Method to solve the horizontal displacement of joint D in mm of the truss system…

A:

Q: If F3 = 9 kN, 0 = 30°, and ø = 45°, determine the magnitude and coordinate direction angles of the…

A: F1=-10cos60o×sin30o×i+10cos60o×cos30o×j-10sin60o×k     =-2.5i+4.33j-8.66kF2=-8×35i+8×45k…

Q: Considering the beam below, EI is constant in all beams. 3 kN 2 kN/m C 1 m. 1 m, 5m 7m B 8 kN/m D 4.…

A: Given:Required:Deflection at midspan of beam CDDeflection along AB directly below support CSlope at…

Braced cuts

The braced cut is a method of providing lateral support to the soil in foundation trenches, to prevent the trenches from deformation by the caving in of soil and resisting it from moving laterally. During shallow excavation in firm soil, generally, slopes are provided to resist the caving in of soil. During shallow excavation in soft soil and deep excavation, the chances of caving in of soil increase. Hence, it becomes necessary to make a provision to resist the deformation of trenches due to caving in of soil. The braced cut is the method used for such conditions. The excavation using braced cuts is a bit uneconomical as compared to the traditional open-cut excavation method but provides better safety than the cut excavation method.