...62 GO During a jump to his partner, an aerialist is to make a quadruple somersault lasting a time t = 1.87 s. For the first and last quarter-revolution, he is in the extended orientation shown in Fig. 11-55, with rotational inertia I₁ = 19.9 kg. m² around his center of mass (the dot). During the rest of the flight he is in a tight tuck, with rotational inertia I2 = 3.93 kg·m². What must be his angular speed @2 around his center of mass during the tuck? W2 Tuck 12 Parabolic @1 11 Release @1 path of aerialist I Catch

University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter11: Angular Momentum
Section: Chapter Questions
Problem 72P: An ice skater is preparing for a jump with turns and has his arms extended. His moment of inertia is...
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...62 GO
During a jump to his partner, an aerialist is
to make a quadruple somersault lasting a time t = 1.87 s. For the
first and last quarter-revolution, he is in the extended orientation
shown in Fig. 11-55, with rotational inertia I₁ = 19.9 kg. m² around
his center of mass (the dot). During the rest of the flight he is in a
tight tuck, with rotational inertia I2 = 3.93 kg·m². What must be his
angular speed @2 around his center of mass during the tuck?
W2
Tuck
12
Parabolic
@1
11
Release
@1
path of
aerialist
I
Catch
Transcribed Image Text:...62 GO During a jump to his partner, an aerialist is to make a quadruple somersault lasting a time t = 1.87 s. For the first and last quarter-revolution, he is in the extended orientation shown in Fig. 11-55, with rotational inertia I₁ = 19.9 kg. m² around his center of mass (the dot). During the rest of the flight he is in a tight tuck, with rotational inertia I2 = 3.93 kg·m². What must be his angular speed @2 around his center of mass during the tuck? W2 Tuck 12 Parabolic @1 11 Release @1 path of aerialist I Catch
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