Consider the object subjected to the loading shown in the figure. Take the value of MD to be equal to 6 kN.m. y 10 kN B 2 kN E 2 kN 2 m MD 2 m 2 m x Determine an equivalent force system at point A, using a scalar approach. (Do not include a minus sign in your response.) The value of FRX of the equivalent force system is The value of Fry of the equivalent force system is The value of FRZ of the equivalent force system is The value of MAX of the equivalent force system is The value of MAy of the equivalent force system is The value of MAz of the equivalent force system is KN 1. KN 1. KN 1. kN·m . |kN·m . | kN·m .

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter8: Momentum And Collisions
Section: Chapter Questions
Problem 10CQ
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Consider the object subjected to the loading shown in the figure. Take the value of MD to be equal to 6 kN.m.
y
10 kN
B
2 kN
E
2 kN
2 m
MD
2 m
2 m
x
Determine an equivalent force system at point A, using a scalar approach. (Do not include a minus sign in your response.)
The value of FRX of the equivalent force system is
The value of Fry of the equivalent force system is
The value of FRZ of the equivalent force system is
The value of MAX of the equivalent force system is
The value of MAy of the equivalent force system is
The value of MAz of the equivalent force system is
KN 1.
KN 1.
KN 1.
kN·m .
|kN·m .
| kN·m .
Transcribed Image Text:Consider the object subjected to the loading shown in the figure. Take the value of MD to be equal to 6 kN.m. y 10 kN B 2 kN E 2 kN 2 m MD 2 m 2 m x Determine an equivalent force system at point A, using a scalar approach. (Do not include a minus sign in your response.) The value of FRX of the equivalent force system is The value of Fry of the equivalent force system is The value of FRZ of the equivalent force system is The value of MAX of the equivalent force system is The value of MAy of the equivalent force system is The value of MAz of the equivalent force system is KN 1. KN 1. KN 1. kN·m . |kN·m . | kN·m .
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