Suppose we wish to evaluate limx→0x10sin(2x)+8.Since we know that −1≤sin(θ)≤1 for θ∈R, we must haveCorrect ≤sin(2x)≤ Correct for x≠0. Part 2 of 4 From this, we must have ≤x10sin(2x)≤ for x≠0. ≤x10sin(2x)+8≤ for x≠0.

Suppose we wish to evaluate limx→0x10sin(2x)+8.Since we know that −1≤sin(θ)≤1 for θ∈R, we must haveCorrect ≤sin(2x)≤ Correct for x≠0. Part 2 of 4 From this, we must have ≤x10sin(2x)≤ for x≠0. ≤x10sin(2x)+8≤ for x≠0.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section1.10: Cornoonentsofavector

Problem 1.2QQ: Figure 1.19 shows two vectors lying in the xy-plane. Determine the signs of the x- and y-components...

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Question

Suppose we wish to evaluate limx→0x10sin(2x)+8.

Since we know that −1≤sin(θ)≤1 for θ∈R, we must have

Correct ≤sin(2x)≤ Correct for x≠0.

Part 2 of 4

From this, we must have

≤x10sin(2x)≤ for x≠0.

≤x10sin(2x)+8≤ for x≠0.

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