. To determine the concentration of analyte in a sample a standard additions was performed. A 5.00-mL portion of sample was analyzed and then successive 0.10-mL spikes of 1 600.0- mg/L standard of the analyte were added, analyzing after each spike. The following table shows the results of this analysis. ,mL Signal intensity V spikes 0.00 0.119 0.10 0.231 0.20 0.339 0.30 0.442 Construct the calibration curve, calculate the linear least-squares equation for the data and determine the concentration of analyte in the original sample.
. To determine the concentration of analyte in a sample a standard additions was performed. A 5.00-mL portion of sample was analyzed and then successive 0.10-mL spikes of 1 600.0- mg/L standard of the analyte were added, analyzing after each spike. The following table shows the results of this analysis. ,mL Signal intensity V spikes 0.00 0.119 0.10 0.231 0.20 0.339 0.30 0.442 Construct the calibration curve, calculate the linear least-squares equation for the data and determine the concentration of analyte in the original sample.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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
Transcribed Image Text:2. To determine the concentration of analyte in a sample a standard additions was performed.
A 5.00-mL portion of sample was analyzed and then successive 0.10-mL spikes of 1 600.0-
mg/L standard of the analyte were added, analyzing after each spike. The following table
shows the results of this analysis.
Vspike, mL Signal intensity
0.00
0.119
0.10
0.231
0.20
0.339
0.30
0.442
Construct the calibration curve, calculate the linear least-squares equation for the data and
determine the concentration of analyte in the original sample.
![3. The following results were obtained for the analysis of phenanthrene using isotopically
labeled phenanthrene as an internal standard. What is the concentration of the analyte in the
sample?
Sanalyte
[phenanthrene], mM
SIs
BiologyEnvsnr
0.50
0.514
me93Science
1.25
0.993
2.00
1.486
3.00
2.044
4.00
2.342
sample
1.024](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F63a81728-8312-489e-a39f-f8ed63ec68fb%2Fd67515d3-a54e-4295-83b2-e515483fa7c2%2F1948kzb_processed.png&w=3840&q=75)
Transcribed Image Text:3. The following results were obtained for the analysis of phenanthrene using isotopically
labeled phenanthrene as an internal standard. What is the concentration of the analyte in the
sample?
Sanalyte
[phenanthrene], mM
SIs
BiologyEnvsnr
0.50
0.514
me93Science
1.25
0.993
2.00
1.486
3.00
2.044
4.00
2.342
sample
1.024
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