.   Predict the elongation for a weld with an oxygen content of 0.15% and a nitrogen content of 0.01%.   b.   If two welds both have a nitrogen content of 0.006%, and their oxygen content differs by 0.05%, what would you predict their difference in elongation to be?   c.   Two welds have identical oxygen contents, and nitrogen contents that differ by 0.005%. Is this enough information to predict their difference in elongation? If so, predict the elongation. If not, explain what additional information is needed.

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The article “Advances in Oxygen Equivalence Equations for Predicting the Properties of Titanium Welds” (D. Harwig, W. Ittiwattana, and H. Castner, The Welding Journal, 2001:126s–136s) reports an experiment to predict various properties of titanium welds. Among other properties, the elongation (in %) was measured, along with the oxygen content and nitrogen content (both in percent). The following MINITAB output presents results of fitting the model

 

 

The regression equation is  
Elongation = 46.80 – 130.11 Oxygen – 807.1 Nitrogen + 3580.5 Oxy*Nit  
Predictor Coef SE Coef T P  
Constant 46.802 3.702 12.64 0.000  
Oxygen – 130.11 20.467 – 6.36 0.000  
Nitrogen – 807.10 158.03 – 5.107 0.000  
Oxy*Nit 3580.5 958.05 3.737 0.001  
S = 2.809 R-Sq = 74.5% R-Sq(adj) = 72.3%  
Analysis of Variance
Source DF SS MS F P
Regression 3 805.43 268.48 34.03 0.000
Residual Error 35 276.11 7.89    
Total 38 1081.54      
                     

 

 

 

a.   Predict the elongation for a weld with an oxygen content of 0.15% and a nitrogen content of 0.01%.

 

b.   If two welds both have a nitrogen content of 0.006%, and their oxygen content differs by 0.05%, what would you predict their difference in elongation to be?

 

c.   Two welds have identical oxygen contents, and nitrogen contents that differ by 0.005%. Is this enough information to predict their difference in elongation? If so, predict the elongation. If not, explain what additional information is needed.

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