. Miniature wings (X") in Drosophila result from an X-linked allele that is recessive to the allele for long wings (X *). Give the genotypes of the parents in each of the following crosses. Male Female Male offspring Female offspring parent parent 231 long, 250 a. long long 560 long miniature 250 miniature b. miniature long 610 long 632 long 410 long, 417 miniature 412 long, 415 c. miniature long miniature 417 miniature 415 miniature d. long 761 long 630 long miniature 753 miniature e. long long 625 long

. Miniature wings (X") in Drosophila result from an X-linked allele that is recessive to the allele for long wings (X *). Give the genotypes of the parents in each of the following crosses. Male Female Male offspring Female offspring parent parent 231 long, 250 a. long long 560 long miniature 250 miniature b. miniature long 610 long 632 long 410 long, 417 miniature 412 long, 415 c. miniature long miniature 417 miniature 415 miniature d. long 761 long 630 long miniature 753 miniature e. long long 625 long

Human Anatomy & Physiology (11th Edition)

11th Edition

ISBN:9780134580999

Author:Elaine N. Marieb, Katja N. Hoehn

Publisher:Elaine N. Marieb, Katja N. Hoehn

Chapter1: The Human Body: An Orientation

Section: Chapter Questions

Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...

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A. You cross a true-breeding sunflower, with yellow flowers and black seeds, with another true-breeding sunflower, with white flowers and green seeds. All of the F1 generation have yellow flowers and green seeds. Create allele symbols and genotypes for these genes and create a representation of this cross, which is consistent with the stated premises. Show your work. B. Upon completing an F1xF1 cross of the yellow flower, green seed sunflowers, you observe the following phenotype classes of offspring in the F2: 250 Yellow flowers and black seeds; 250 white flowers and green seeds; 500 yellow flowers and green seeds. A test cross of the yellow flower, green seed F1 generation generates the following offspring: 500 white flowers and green seeds; 500 yellow flowers and black seeds. Do these observations taken together, of the F1, F2, and test cross offspring, respectively, represent violations of Mendel's first law, Mendel's second law, or both? Explain your answer.
In Drosophila, a gene controls body color producing either normal body color or the mutant form black body color (bl. A second gene controls wings. The flies either have normal wings or are wingless (wn). A cross is made between a homozygous wild type fly and fly with black body and wingless. A test cross was then performed. The following progeny was observed: Phenotype # Observed Wild Type 405 Normal, wingless 85 Black, normal 100 Black, wingless 410 A. List the genotypes of the original parents. B. List the genotypes of the testcross. C. Are these two genes linked? How do you know? Edit Format Table 12pt v Paragraph v BIUA
Write the cross using correct symbols. What kind of cross is this called?
Explain this to me…..
Fruit flies with the genotypes Xg+h+Xgh and XghY are crossed. Note that two X-linked loci are being evaluated, and the presence of a + indicates a dominant allele. The homogametic offspring will.... 1. express either the dominant or the recessive phenotypes for both g and h. 2. all express both dominant phenotypes. 3. express neither phenotype. 4. all express both recessive phenotypes.
Please answer fast:-
If a Drosophila female that is homozygous for an X-linked recessive mutation is bred with a male that carries the corresponding wild-type allele, the offspring will..... a. show the mutant phenotype in all individuals. b. be uniform wild-type. c. show a phenotype intermediate to the parents' phenotype. d. show the mutant phenotype in all males and the wild-type phenotype in all females. e. have mutant and wild-type males and mutant and wild-type females.
b. What is the probability that the mating of Fifi with the described male will produce a kitten affected with the disease? Please help
8. In guinea pigs, the allele for black fur (B) is dominant over the allele for white fur (b). Similarly, the allele for straight hair (H) is dominant over the allele for having rough hair (h). Pure breeding rough haired guinea pigs with black fur were crossed with pure breeding straight haired guinea pigs with white fur. a. State the genotype and the phenotype of the F1 individuals produced as a result of this cross.b. Two F1 offspring were mated together. Calculate the expected ratio of phenotypes in the F2 generation.c. Show the completed Punnett square below.
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Dr. P was using Drosophila to follow the inheritance patterns of two traits: body shape and wing size. Dr.P began her experiment by crossing wild type, homozygous dominant, males with double mutant, homozygous recessive, females. She then performed a testcross by mating Fi generation males with double mutant, homozygous recessive, females and observed the phenotypes of the F2 generation. Shorthand of the different alleles is annotated as follows: Wild type round body shape allele = b* Wild type large wing size =w* Mutant rectangle body shape allele = b Mutant small wing size = w A) Complete the table by indicating the genotypes for each generation of male and female flies. Male Genotype Female Genotype P generation F, generation testcross When Dr.P characterized and counted the F2 phenotypes, she determined the following: Round-large Rectangle-small 332 flies Round-small Rectangle-large 357 flies Number of flies 344 flies 360 flies B) Using the data above, would you be surprised (yes…
Color blindness in humans is an X-linked recessive trait. This means that... O a. Females are more likely to be color blind than males b. The gene associated with color blindness is found on the X chromosome, and an individual must have one (in males) or two (in females) mutant copies of the allele in order to be diagnosed as being color blind