Lab 4 Conservation of linear momentum online (mine)

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Conservation of Linear Momentum Goal: To investigate the Law of Conservation of Linear Momentum in collisions. Copy this file and fill in the tables directly on the document. Add a screenshot for all the activities. Simulation Used: Collision Lab from the PhET at the Univ0ersity of Colorado. Preliminary Settings. ● Open the simulation and select the tab Explore 1D . ● From the menu on the right, select: Values and Velocity. ● In the screen below, click on More Data. ● Uncheck Reflecting borders. Activity 1: Elastic Collisions in one dimension. One ball is initially at rest. On the menu to the right, slide the indicator all the way to the right for a perfectly elastic collision. ● For the given masses and initial speeds of the two balls, determine the velocity and momentum after the collision. ● Place the two objects one in front of the other, so that they will collide. ● Fill out all the tables. Add a screenshot of your work on the simulation for each table you are completing. In total seven screenshots, please place them at the end of each table.
  Ball     Mass (kg)   Before the Collision After the Collision       V (m/s)     Momentum (kg.m/s)     v (m/s)     Momentum (kg.m/s)   1 1.50 0 0 -1.49 -2.23 2 2.00 -1.3 -2.60 -0.19 -0.37 Total Momentum initial (Sum of momentum for ball 1 plus momentum for ball 2, initial) = -2.60kg m/s Total Momentum final (Sum of momentum for ball 1 plus momentum for ball 2, final) = -2.60kg m/s Screenshot of the simulation with the collision for the table above.   Ball     Mass (kg)   Before the Collision   After the Collision       v (m/s)     Momentum (kg.m/s)     v (m/s)   Momentum (kg.m/s) 1 0.40 1.70 0.68 -1.02 -0.41 2 1.60 0 0 0.68 1.09 Total Momentum initial= 0.68kg m/s
Total Momentum final= 0.68kg m/s Screenshot of the simulation with the collision for the table above. Question: In these two trials, is the momentum conserved? Why? Answer : Yes, the momentum is conserved because the initial and final momentum are the same Activity 2: Elastic Collisions in one dimension. Balls 1 and 2 initially moving in the same direction.   Ball     Mass (kg)   Before the Collision After the Collision       v (m/s)     Momentum (kg.m/s)     v (m/s)     Momentum (kg.m/s)   1 3.00 1.80 5.40 0.40 1.20 2 3.00 0.40 1.20 1.80 5.40
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Total Momentum initial = 6.6kg m/s Total Momentum final = 6.6kg m/s Screenshot of the simulation with the collision for the table above. Question: Is the momentum conserved? Why? Answer: Yes, final and initial momentum are equal.
Activity 3: Elastic Collisions in one dimension. Balls 1 and 2 initially moving in the opposite direction.   Ball     Mass (kg)   Before the Collision After the Collision       v (m/s)     Momentum (kg.m/s)     v (m/s)     Momentum (kg.m/s)   1 3.00 1.80 5.40 -0.60 -1.80 2 3.00 - 0.60 -1.80 1.80 5.40 Total Momentum initial= 3.6kg m/s Total Momentum final = 3.6kg m/s Screenshot of the simulation with the collision for the table above
  Ball     Mass (kg)   Before the Collision   After the Collision         v (m/s)     Momentum (kg.m/s)     v (m/s)     Momentum (kg.m/s)     1       0.50     1.40 0.70 -2.80 -1.40   2       1.50     -1.40 -2.10 0 0 Total Momentum initial= -1.40kg m/s Total Momentum final= -1.40kg m/s Screenshot of the simulation with the collision for the table above. Question: In these two trials, is the momentum conserved? Why?
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Answer : Yes, the momentum is conserved because the initial and final momentum are equal. Activity 4: Inelastic Collisions. On the menu to the right, slide the indicator all the way to the left to ensure perfectly inelastic collision.   Ball     Mass (kg)   Before the Collision   After the Collision         v (m/s)     Momentum (kg.m/s)     v (m/s)     Momentum (kg.m/s)   1 0.70 2.60 1.82 1.30 0.91 2 0.70 0 0 1.30 0.91 Total Momentum initial= 1.82kg m/s Total Momentum final = 1.82kg m/s Screenshot of the simulation with the collision for the table above.
  Ball     Mass (kg)   Before the Collision   After the Collision         v (m/s)     Momentum (kg.m/s)     v (m/s)     Momentum (kg.m/s)   1 3.00 2.40 7.20 1.87 5.61 2 0.50 -1.30 -0.65 1.87 0.94 Total Momentum initial = 6.55kg m/s Total Momentum final = 6.55kg m/s Screenshot of the simulation with the collision for the table above. Question: In these two trials, is the momentum conserved? How do you know? Answer : The momentum is conserved because the initial and final momentum are equal. Question: In the last trial, is kinetic energy conserved? Show the calculations for the sum of the initial kinetic energy of mass 1 and mass 2 and compare it with the sum of the final kinetic energy of mass 1 and mass 2. Initial = ½ (3) (2.40) ^2 + ½ (0.5) (-1.3) ^2 = 9.06 J
Final= ½ (3) (1.87) ^2 + ½ (0.5) (1.87) ^2 = 6.119 J The kinetic energy was not conserved because the sum of the initial KE and the sum of the final KE are not equal. The initial (9.06J) is greater than the final (6.119J).
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