Lab 5 report

docx

School

CUNY Queensborough Community College *

*We aren’t endorsed by this school

Course

112

Subject

Physics

Date

Dec 6, 2023

Type

docx

Pages

2

Uploaded by MateFang1930

Report
Lab 5 report The purpose of this lab was to understand how to determine how to measure the angular diameter and the physical radius. Distance is used to identify them, and perspective is how we see objects and look smaller, for example sometimes a penny looks bigger than the sun because it is closer to us. The most common way to get these values is through a pinhole camera, which is made manually and can be made with a paper clip, or a pencil and it will get projected on the other side of the hole. The Greek letter alpha is used to know the angle that is made on the diameter and the physical radius. Since it is bisected there is a relation between the tangent of half of alpha = sun’s radius/distance of the tube. On Part 1, the tube length of the moon was given, which was 105 cm so from there we were able to get the other values and by looking at the picture provided for the lab. Sun Moon 0.6 cm 1.1 cm= image width in cm 105 cm 105 cm= tube length in cm 0.002855 0.005238 image half- width/tube length 0.1637 0.3=0.5 x angular diameter 0.3274 0.6= angular diameter For method 2, first there is to identify the angle alpha that was created when the sun moves from one side of the pinhole to the other, so the time that it took to pass from one side to the other is identified in a proportion. In this case the sun’s angle is 0.5625 to get this value I had to identify the time of transit in seconds times 360 degrees divided by 86,400 Sun’s angle: (135)(360)/86400s = 0.5625 The date used was Nov. 25 and I used a chronometer to get the values of the sun and the moon. Sun Moon Time of image’s initial contact with reference line 84s 30s Time that the image has fully crossed reference line 217 s 157s Time difference in seconds 135 s 130 s Angular diameter in degrees 0.5626 0.1986
On part 2 of the method 2, the date and declination of the moon are given so in that I was able to identify the declination of the sun on the equator. This is another way to get the sun’s angular diameter Sun Moon Declination -20 -14.5 Correction factor 0.94 0.97 Angular diameter x correction factor 0.53 0.10 - Which of the methods you used to find the angular diameter of the sun do you think gave the more accurate value? In my opinion, Proportion of the sun’s angular diameter divided by 360 degrees equal to the average length in s divided by 360, so the first one because I was able to get the time in seconds several times and could get a better accuracy on the angular diameter, because the video was provided, and I was able to see it until I got the average of time. On page 6, it is set to identify the sun’s physical radius with the sun’s angular diameter and the earth-sun distance (150,000,000km). I chose the one used on SunMovie because I think the value is more accurate than the others. Tan(0.5X0.5625)X150,000,000km = 736,316.692 km For the next step, the diameter of the sun is identified by multiplying the radius by 2 73,316.592 X 2 = 1,472,633.3844 km Then to answer the last question: this value had to be divided by 12800 km 1,472,633.3844/12800= 115.049 So, the Earth’s physical diameter would fit 115.049 times into Sun’s diameter. In conclusion, this lab helped us understand how to measure the angle of the Sun and Moon in different ways and its radius and diameter. I believe that the most accurate way to get these values were through the pinhole camera video and I was able to repeat it as many times as I could to get more accurate values. Also I think that by using the equator is another good way to understand that a correction to the angular diameter found on the pinhole camera had to be made according to the date and declination, since it is something we already learned on the previous labs.
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help