Lab 1 - Tensile Testing of Isotropic Materials
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Tensile Testing of Isotropic Materials
Lab 1
–
Aditya Kannan
Introduction
The objective of this lab report is to understand the utility and results of tensile testing a material. Using
an Instron tensile testing machine and a digital image correlation simultaneously, we obtained data to
observe the stress vs strain for a given piece test specimen made of 5052 aluminum alloy.
Part 1: Instron Tensile Tester
Discussion of relevant concepts
Engineering constants relevant to this experiment
An isotropic material is characterized by its mechanical properties being independent of direction,
meaning it exhibits the same behavior in all directions. The relevant constants for isotropic materials
include Young's Modulus (E, Pascals), Yield Point,
Shear Modulus (G), and Poisson's Ratio (ν). Young's
Modulus measures the material's stiffness in tension, while Shear Modulus quantifies its resistance to
shear deformation. Poisson's Ratio describes the material's tendency to contract laterally when
stretched longitudinally.
Stress-strain curve
Figure 1: A common stress/strain curve By Nicoguaro - Own work, CC BY 4.0,
https://commons.wikimedia.org/w/index.php?curid=89891144
The stress-strain curve typically exhibits several distinct regions:
•
Elastic Region
: In this initial phase, the material behaves elastically, meaning it returns to its
original shape when the load is removed. Young's Modulus (E) can be determined from the slope
of this linear region, reflecting the material's stiffness.
•
Yield Point
: Beyond the elastic region, the material enters the plastic deformation phase. The
yield point signifies the stress at which plastic deformation begins.
•
Ultimate Tensile Strength:
This is the point on the curve where the material reaches its
maximum stress before necking or localized thinning occurs. Ultimate Tensile Strength (UTS) is
the highest stress the material can endure under tension.
•
Fracture Point:
The curve terminates at the fracture point, indicating the stress at which the
specimen ruptures.
Experimental setup
First, the crossectional area of the sample was found by measuring the width and thickness using a pair
of calipers. Then, the 5052 aluminum alloy specimen, prepared in a dogbone shape, was securely
clamped into the testing machine. The data recording was started on the testing machine and a constant
tensile load was applied along the axis of the specimen at a controlled rate while the machine measured
the corresponding deformation via the crosshead displacement.
Part 2: Digital Image Correlation (DIC)
Discussion of relevant concepts
Digital Image Correlation (DIC) is a non-contact optical measurement used to analyze the deformation
and strain distribution on the surface of a specimen subjected to mechanical testing. DIC works by
tracking the displacement and deformation of small subsets or "speckles" on the specimen's surface.
These speckles serve as natural or applied markers that can be tracked between images taken before and
during deformation. While DIC is capable of tracking deformation on both axes, we are only using data in
the y-axis for this report.
Experimental setup
A camera was carefully positioned to capture images of the specimen's surface, and proper lighting and
focusing were ensured to obtain a clear video. The speckle pattern on the sample was pre-applied via a
spray by the lab assistant. To begin the experiment, we began recording via the software the camera was
configured with. Post-capture, the footage was used to analyze deformation. The software compared the
reference image with the pre-defined deformed images, tracking the displacement and deformation of
individual speckles. From the displacement data, strain fields across the specimen's surface were
computed, providing us with deformation data on a selected region of the sample.
Results
The crossectional area of the sample was measured to be
7.28 𝑚𝑚
2
or
7.28 ∗ 10
−6
𝑚
2
. The length of
the sample is
31.33 𝑚𝑚
or
3.13 ∗ 10
−2
𝑚
.
The data from the tensile testing machine was received in the form of crosshead displacement (
𝑚𝑚
) and
force (
𝑘??
). From the data obtained from the DIC, the y-axis displacement measurements were used.
Strain values were calculated by converting
𝑚𝑚
to
𝑚
and dividing by the length of the sample. Stress
values were calculated by converting
𝑘??
to
𝑁
and dividing by the crossectional area of the sample.
Since DIC does not yield stress measurements, the force data from the tensile testing machine was
extrapolated and correlated with the displacement data of the DIC to provide the graphs below.
The consolidated experimental data obtained from the testing machine and DIC is plotted in the graph
below.
The Youngs Modulus was calculated by finding the slope of the linear (elastic region) between
0
𝑃𝑎
to
2.75 ∗ 10
−8
for the Instron tensile testing machine data and
0 𝑃𝑎
to
2.76 ∗ 10
−8
𝑃𝑎
for the DIC data.
Below are graphs of the elastic region from both data sources with treadlines plotted.
Instron Tester
DIC
Youngs Modulus
1.82 ∗ 10
10
𝑃𝑎
6.86 ∗ 10
10
𝑃𝑎
Yield Point
5.946 ∗ 10
−4
𝑚
4.34 ∗ 10
−3
𝑚
Ultimate Tensile Strength
3.38 ∗ 10
8
𝑃𝑎
3.37 ∗ 10
8
𝑃𝑎
Fracture Point
3.36 ∗ 10
8
𝑃𝑎
3.36 ∗ 10
8
𝑃𝑎
Table 1: Results from both data sources
0.00E+00
5.00E+07
1.00E+08
1.50E+08
2.00E+08
2.50E+08
3.00E+08
3.50E+08
4.00E+08
0.00
0.02
0.04
0.06
0.08
0.10
0.12
0.14
0.16
0.18
Stress (Pa)
Strain (m/m)
Stress-strain curve
Instron Tester
DIC
y = 1.82E+10x + 1.51E+07
R² = 9.90E-01
0.00E+00
5.00E+07
1.00E+08
1.50E+08
2.00E+08
2.50E+08
3.00E+08
3.50E+08
-0.01
0.00
0.01
0.01
0.02
0.02
Stress (Pa)
Strain (m/m)
Elastic region (Instron Tester)
y = 6.86E+10x + 4.83E+07
R² = 9.95E-01
0.00E+00
5.00E+07
1.00E+08
1.50E+08
2.00E+08
2.50E+08
3.00E+08
3.50E+08
0.00E+00 1.00E-03 2.00E-03 3.00E-03 4.00E-03
Stress (Pa)
Strain (m/m)
Elastic region (DIC)
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Discussion
The fracture surface was not normal to the direction of loading due to aluminum's ductility. Ductile
materials like aluminum undergo plastic deformation before fracturing, causing localized necking and
misalignment of the fracture surface with the loading direction.
Below is
Hooke’s Law for 1D and 2D plane stress specimens:
1D:
𝜎 = 𝐸𝜀
2D:
[
𝜎
?
𝜎
?
𝜏
??
]
= [
𝐸
ν
0
ν
𝐸
0
0
0
𝐸
2(1+ν)
] ∙ [
𝜖
?
𝜖
?
𝛾
??
]
An extensometer directly measures strain on the specimen's surface, providing more precise strain data
than crosshead movement measurement of a testing machine. It contributes to accuracy by eliminating
machine compliance, offering localized measurements and reducing errors in strain data.
Possible sources of errors
Machine compliance, misalignment, strain localization, temperature fluctuations, specimen preparation,
data acquisition, and anisotropic material behavior.
Advantages & Disadvantages of Digital Image Correlation (DIC )
Advantages: Non-contact measurement, high spatial resolution, full-field strain measurement, and
applicability to various materials.
Disadvantages: Complexity of setup and calibration, surface preparation, computational intensity, limited
to surface measurements, and sensitivity to environmental factors.
Related Documents
Related Questions
1. A tensile test was conducted on a metal "505" specimen and the following stress-strain curves
were generated, both curves generated from the same set of data. Use the graphs to fill in the
mechanical properties of the material tested in the box below. Don't forget units!
Stress vs Strain
Stress, psi
Stress, psi
80000
70000
60000
50000
40000
30000
20000
10000
0
0.00
80000
70000
60000
50000
40000
30000
20000
10000
0.02
0
0.000 0.002
0.04
0.004
0.06
0.006
0.08
0.10
Strain
Stress vs Strain
0.008
0.12
Elastic Modulus, E:
0.2% Offset Yield Strength, oo:
Tensile Strength, ou:
Breaking Strength, of:
% Elongation:
0.14
0.010 0.012 0.014
Strain
0.16
0.18
0.016 0.018
0.20
0.020
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Flag question
You have been given the following test sample data following mechanical testing of 15 test pieces of a modified Alumina.
What is the Weibull modulus of this material?
Would you advise the use of this material over one with a Weibull Modulus of 19.6 and a mean failure stress of 270 MPa, if you
anticipate that the peak stress on the material could be 255 MPa?
Sample
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
Select one or more:
Failure Stress (MPa)
297
293
270
300
260
286
265
295
4
293
280
288
263
290
298
275
arrow_forward
Yield strength, ultimate tensile strength, linear coefficient of thermal expansion, modulus of elasticity (E), proportional limit, and rupture strength are all
examples of mechanical properties of engineering materials.
O True
False
A non-destructive test is any examination of an object in any manner which will not impair the future usefulness of the object. Non-destructive tests include:
magnetic-particle, impacting testing, radiography, eddy current, and fluorescent-penetrant.
O True
O False
One way to make a metal stronger is to increase the metal's grain size.
O True
O False
--- OL T
A metal that has a crystalline structure is called amorphous.
O True
O False
arrow_forward
6. State your answers to the following questions.Strain Gauge represents the deformation of a material through a change in resistance. If so, explain how temperature will affect the strain gauge in the experimental environment.①:In this experiment, the Strain Gauge measures the strain in micro units. Explain one possible error factor when applying a load by hanging a weight on the material with the strain gauge attached. (Hint: It is easy to shake by hanging the weight using a thread)①:
arrow_forward
Figure 1 shows the tensile testing results for different materials. All specimens have an initial
diameter of 12 mm and an initial gauge length of 50 mm.
300
250
Low carbon steel
Network polymer
200
Crystalline polymer
150
Amorphous polymer
100
50
5
10
15
20
25
30
Strain (%)
Figure 1: Stress-strain curve
b. Determine the following parameters for each material:
• the tensile strength
the 0.2% offset yield strength
the modulus of elasticity
• the ductility
Stress (MPa)
LO
arrow_forward
3. Two specimens with the same dimensions and made from two different materials, A and B, were subjected to tensile testing. The percentage
reduction in the area of the specimen made of material 'A' was calculated 3 times that of the specimen made of material B. In this case,
O A lthe ductility of material A and B is equal
O Bthe material A is brittle and material B is ductile
O Cthe material B is more ductile than material A
O D nhe material A is more ductile than material B
1.
20
O Aramak için buraya yazıin
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Question 1
You are working on a design team at a small orthopaedic firm. You have been asked to select a cobalt-
chrome-molybdenum (CoCr) material that will not experience plastic deformation under a specific mechanical test, as follows...
A tensile stress is applied along the long axis of a solid cylindrical rod that has a diameter of 10 mm. An applied load of some
magnitude F produces a 7x10-³ mm change in diameter (see figure below, original shape is blue, elongated shape is unshaded).
Q1E: Of those two materials (F75 CoCr alloy (as cast) and F90 CoCr alloy (hot forged)), which materials would you select to assure
that the deformation is entirely elastic (No yield!)?
arrow_forward
Question 1
You are working on a design team at a small orthopaedic firm. You have been asked to select a cobalt-
chrome-molybdenum (CoCr) material that will not experience plastic deformation under a specific mechanical test, as follows...
A tensile stress is applied along the long axis of a solid cylindrical rod that has a diameter of 10 mm. An applied load of some
magnitude F produces a 7x10-³ mm change in diameter (see figure below, original shape is blue, elongated shape is unshaded).
Q1G: If your design required using the new material to create a wire, what is the largest diameter that would lead to ductile
behavior while still avoiding plastic deformation when exposed to the above loading conditions?
arrow_forward
I need the answer as soon as possible
arrow_forward
Consider the graph below for 3 test samples A, B and C of the same metal
composition which have been cold-worked, but to different extents. If you had to
sort the samples by the degree of cold-working they have undergone, how would
you rank them?
Stress (MPa)
600
500
4006
300
200
100
0
A
B
0.05
1
0.1
0.15
Strain
Select the correct answer:
a. A
arrow_forward
Can someone please help me to correctly solve all the following parts of this question. Thank you!
arrow_forward
How did temperature affect the toughness of the specimens?
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Don’t use ai pls
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UzNDU3NTYyMjk0/a/MjYOMzAwMjMOOTM5/details
Further questions
4.The graphs show how the extension changes with stretching force for four different materials.
a. Which two graphs show materials that follow Hooke's law?
A
B
b. Which two graphs show materials that become less stiff as
they are stretched?
force
force
D
C. Which graph shows a material that maintains the same
stiffness throughout?
force
force
1. A force of 20N stretches a spring by 0.5m. The spring obeys Hooke's law.
a. Calculate the spring constant including a suitable unit.
b. How much force must a man use to stretch it by 1.5m?
5. A car has a weight of 240OON which is distributed equally over all four wheels. Each wheel has a spring of
spring constant 400N/cm.
a.
Determine the force through the spring on each wheel.
b. Calculate the compression of each spring when the car rests on the ground.
6.In a spring experiment the results were as follows:
Force (N)
Length (mpm
1
2
4
6.
7
50
58
70
74
82
9n
102
125
LELL
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A sample of crosslinked polvisoprene rubber undergoes a constant strain rate axial tension experiment
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please solve part b, this is past paper and just iam studying, mechanical engineering
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(d) Following experimental data (TableQ1b) has obtained from the
torsion test for the specimen dimension given in Table Q1a.
Determine the material of a circular bar. (Take the material
Poisson's Ratio as 0.32)
Table Q1a Specimen Dimensions
Dimensions
Material
Diameter (mm)
6
Length (mm)
77.15
TableQ1b Experimental Results from Torsion test
Angular Deflection
Degree
Radian
Torque/Nm
0.5
0.008727
0.06
1
0.017453
0.47
1.5
0.02618
0.76
2
0.034907
1.01
2.5
0.043633
1.32
3
0.05236
1.65
3.5
0.061087
1.99
4
0.069813
2.32
4.5
0.07854
2.66
5
0.087267
3.00
5.5
0.095993
3.33
6
0.10472
3.64
10
0.174533
5.92
20
0.349066
7.74
30
0.523599
8.07
40
0.698132
8.17
50
0.872665
7.93
60
1.047198
8.10
70
1.221731
8.2
80
1.396264
8.4
90
1.570797
8.24
100
1.74533
8.7
110
1.919863
8.7
120
2.094396
8.7
180
3.141594
9.02
240
4.188792
9.11
300
5.23599
9.48
360
6.283188
9.51
420
7.330386
9.71
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