Dynamics Lab 1 Group 6 - Google Docs
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Uploaded by DoctorCloverButterfly57
Department of Mechanical and Industrial Engineering
ME 3455: Dynamics and Vibrations (Spring 2023)
Trajectories with Aerodynamic Drag
Submitted by
Gili Fang, Taylor Leibig, Dominic Natale, & Declan Rogers
Abstract
In an effort to further explore drag and its effect on projectiles an experiment with four
trials was conducted using a tennis ball, iphone camera, tracker software, and matlab code. A
tennis ball was thrown and filmed in slow motion with an iphone, then analyzed using tracker
software. The data collected from the tracker software was imported into matlab to find results
and plot them. On average the tennis ball traveled 2.475 ft with a velocity of 10.03 ft/s. The
average experimental drag coefficient was .4967.
Date Submitted:
2/19/2023
Date Performed:
1/30/2023
Lab Section:
30432
Course Instructor:
Jahir Pabon
Lab TA:
Zahra Karimi
List of Symbols
Name
Symbol
Terminal Velocity
𝑣
?
Initial Velocity
𝑣
0
Angle
θ
Acceleration due to gravity
𝑔
Height
ℎ
Distance traveled
?
Drag coefficient
𝐶
𝑑
Density of fluid
ρ
Average velocity
𝑉
Cross sectional area
𝐴
Table 1- List of symbols
Introduction
Drag is generated by the interaction between a body and a fluid. Friction between the
molecules of air and the surface of the moving object create a force in the opposite direction of
the object’s motion. The magnitude of the drag force is dependent on aspects of the system such
as the density of the fluid traveled through, the size and shape of the body, and the velocity the
object travels with, however, its direction is always the opposite of the direction of velocity.
When it comes to projectile motion, drag has the ability to reduce the horizontal distance the
projectile travels and reduce the range of velocity, when compared to a situation where drag is
negligible. As velocity increases, the drag force increases and approaches the magnitude of the
force of gravity. When it does reach this point, a terminal velocity is reached. This value is the
maximum velocity an object in free fall can reach when drag is present and occurs at the same
time the acceleration of the trajectory is equal to zero.
The purpose of this experiment is to simulate projectile motion in order to observe the
effects of drag on an object in air. To do this, a tennis ball was thrown and its trajectory was
recorded. After calculating the distance traveled, and initial conditions (velocity, angle of
inclination, and height) it was possible to compare the results with other models and verify the
effect of drag on the simulated trajectory.
Theory and Methods
Given an initial velocity V
0
, an initial height y
0
, and initial angle of trajectory 0
0
, we can
use the equation:
to find the horizontal distance of
∆? = ?𝑜𝑠(θ)𝑣
0
×
𝑣
0
?𝑖𝑛(θ)+
(𝑣
0
?𝑖𝑛(θ))
2
+2𝑔ℎ
𝑔
the foam ball.
Figure 1- Free Body Diagram of trajectory with Equations of Motion
Using Newton’s Second law of
, we can derive the equations of motion in the
𝐹 = 𝑚𝑎
trajectories in the x and y direction as seen above.
The mass of an object on a free falling object will change how fast the object is
accelerating towards the ground. The more massive the object is the more they are acted upon by
the force of gravity causing the object to need a greater air resistance force to even it out. The
cross sectional area of an object will impact the amount of air resistance resulting on that object.
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If the object has an increase in cross sectional area, then there will be an increase in the amount
of air resistance.
Using the equation
we can calculate the analytical terminal velocity of
𝐹
?
=−
ρ?
𝐷
𝐴𝑉|𝑉|
2
the foam ball to be 50.78 ft/s. If we dropped the ball vertically, we used the MATLAB code to
calculate the time it would take for the foam ball to reach 99% of its terminal velocity to be 4.17
seconds. Also using MATLAB, we were able to find the minimum height you would need to
drop the ball for it to reach 99% of its terminal velocity to be 156 ft which you can see below.
To begin our procedure we started by setting out smartphones to 240fps for a slow
motion high speed video. Then we held the camera stable, perpendicular to the wall, to allow us
to see the full travel of the foam ball in front of the pre-made grid without moving the camera.
After we found a good place to keep the camera, we tossed the tennis ball at an arc and recorded
the travel of the ball moving in an arc. We repeated tossing the ball 4 times to make sure we had
sufficient data to use in MATLAB.
Experimental Results
Trial #
1
2
3
4
Initial Velocity (ft/s)
10.55
11.21
10.65
7.72
Initial Vertical Height (ft)
0.798
0.495
0.353
0.200
Initial Angle (°)
66.3
65.2
68.0
44.6
Horizontal Distance Traveled (ft)
2.299
2.780
1.785
3.036
Theoretical Horizontal Distance
With Zero Drag (ft)
2.74
3.19
1.92
3.32
Table 2- Theoretical horizontal distance with no drag based on initial conditions
With an assumed drag coefficient of 0.47 and the initial conditions of each trial, a
MATLAB program was used to determine the theoretical range of the thrown ball and landing
time as shown in the figure below:
Trial #
1
2
3
4
Simulated Range (ft)
2.3299
2.7901
1.7993
1.0455
Simulated Landing Time (s)
0.6940
0.6350
0.6600
0.4580
Table 3- Predicted distance with drag
The trends seen in the following graphs show that the theoretical trajectory of a ball in air
matches the experimental data observed. Each graph consistently shows two curves, one
theoretical and one experimental, that are very close to each other. The second trial portrays the
greatest distance traveled while the last graph gives the shortest distance. While all trials have
very similar drag coefficients, the initial conditions of each trial are different. The second trial
was released with the highest initial velocity in the x direction while the fourth trial was released
with the lowest. These velocities are what propelled the ball in its reach and determined the
distance traveled. The second trial also had a much larger initial angle than the fourth which
allowed the ball to gain more height and distance before it fell.
Using the initial conditions of each trial, a theoretical trajectory was mapped by
modifying the drag coefficient to best imitate the arc of the experimental data. This new
coefficient is shown for each trial and the mean of all four.
Trial #
1
2
3
4
Mean
Determined Drag Coefficient
0.4924
0.5033
0.4891
0.5019
0.496675
Table 4- Experimental drag coefficient
Given these values, the standard deviation was determined to be 0.00699636.
Following the determination of an approximate experimental drag coefficient, the
experimental data and a theoretical arc with this coefficient were graphed together for each trial
as shown in the figures below. The determined coefficients proved to be quite accurate to the
experimental data as the arcs for each trial are very close.
Figure 2- Graph of trial 1
Figure 3- Graph of trial 2
Figure 4- Graph of trial 3
Figure 5- Graph of trial 4
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Discussion and Analysis
This experiment was conducted under the effect of many potential sources of error. Since
the trajectory of the ball was recorded in a room with both the air conditioning running and
windows opened, wind in the room may have had an effect on the flight of the ball. Random
error generated from angled positioning or slight movement of the camera affects all of the data
since the videos are the basis for all conclusions. Additionally, the tracker software used to
obtain the data of this experiment required very meticulous plotting of points on the trajectory of
the ball that could easily be skewed from a view that is not zoomed in enough or incorrect due to
camera movement during the fall.
In the practical application of projectile motion within the game of baseball, wind
conditions play a major role. Utilizing a MATLAB program, the necessary exit velocity of a
home run at Fenway Park hit into left field was determined with the initial conditions as follows:
Weight = 5.125 oz; Circumference = 9.125 in, Exit Angle = 45 degrees; Initial Height = 4 ft;
Target Range = 345 ft; Target Height = 37 ft. Given negligible wind conditions, the required exit
velocity was determined to be 174 ft/s. Given a 10 mph tailwind, the required exit velocity was
determined to be 156 ft/s. Given a 10 mph headwind, the required exit velocity was determined
to be 201 ft/s.
Conclusions
To summarize, the purpose of this experiment was to explore the effect of drag on
projectiles. The experiment utilized a tennis ball, iphone camera, tracker software, and matlab
code and consisted of four trials. On average the tennis ball traveled 2.475 ft with a velocity of
10.03 ft/s. The average experimental drag coefficient was .4967. The average theoretical distance
without drag was 2.793 ft and the average experimental distance traveled was 2.475 ft. Without
drag the tennis ball would have traveled an average of 0.318 additional feet.
Acknowledgments
Thank you to our TA Zahra Karimi for providing a thorough explanation of this lab at the
beginning of class and assisting us with MATLAB issues through helpful insight and guidance.
References
1. S.S. Rao,
Mechanical Vibrations,
Fourth Edition, Prentice-Hall, Inc., New Jersey, 2004.
Appendix A: Matlab Code
global alpha;
global m;
global g;
global tstep;
global tend;
global wind;
Xo=0;
% Initial Horizontal Position (ft)
dia= 2.76;
% Projectile Diameter (in)
rho= 2.38e-3;
% Air Density (slugs/ft^3)
g= 32.2;
% Acceleration Due to Gravity (ft/s^2)
m= 1.98e-3;
% Projectile Mass (slugs)
C= 0.4924;
tend=10;
% Maximum time solved for. Increase
this for more values (s)
tstep=0.001;
% Time Step (s)
nu=(1.516*10^-5)*(3.281*3.281); % Kinematic Viscosity (ft^2/s)
Yo= 0.798;
Vx = 2.954;
Vy = 10.125;
Vo = sqrt(Vx^2 + Vy^2);
%Initial Velocity (ft/s)
T= atan2(Vy,Vx) * 180 /pi;
%Initial Angle (degrees from horizontal)
wind=0;
A=pi*(dia/(2*12))^2;
% Cross-Sectional Area
alpha=.5*rho*C*A;
Re=Vo*(dia/12)/nu;
% Reynolds number calculation
ang=pi*T/180;
t=0:tstep:tend;[t,X,Y,Vx,Vy]=Motioncalc(Xo,Yo,Vo,ang,C);
for count=1:1:length(Y)
if Y(count)<0
break;
end
end
disp('Theoretical
Zero-Drag
Landing
Time
(s):');((Vo*sin(ang)+sqrt((Vo*sin(ang))^2+2*g*Yo))/g)
disp('Simulated 2D Drag Landing Time (s):');t(count-1)
disp('Simulated 2D Drag Landing Point (ft):');X(count-1)
Exp_Data_File
% (change) execute the file contains the experiemental
data = [t, x, y]
plot(X(1:count-1),Y(1:count-1)
,'DisplayName'
,'Theory');
%
plot
theoretical projectile with drag
hold on
plot( (data(:,2)), (data(:,3)+Yo) ); % plot the experiemenal projectile
legend('Theory with drag', 'Experiement')
title('Trajectory'); %Graph title
xlabel('Distance (ft)'); %x-axis label
ylabel('Height (ft)'); %y-axis label
hold off
% calculate mean squared error
xv = linspace(max(X(1),data(1,2)), min(X(end),data(end,2)),200);
ytheo = interp1(X,Y,xv,'pchip');
yexp = interp1(data(:,2), data(:,3)+Yo,xv,'pchip');
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disp('The
MSE
error
between
theory
and
experiment
is:');mean((ytheo-yexp).^2)
Vt=sqrt(m*g/alpha);
[t,Xt,Yt,Vxt,Vyt]=Motioncalc(Xo,Yo,0,-pi/2,C);
% Terminal Velocity Calculation
for i=1:length(Vyt)
if -Vyt(i)>=Vt*0.99
break
end
end
plot(t,-Vyt(:));
xlabel('Time (s)'); % x-axis label
ylabel('Velocity (ft/s)'); % y-axis label
title('Terminal Velocity Simulation')
disp('Analytical Terminal Velocity (ft/s):');Vt
disp('Approx. Simulated Terminal Velocity (ft/s):');-Vyt(i)
disp('Time to 99% of Terminal Velocity (s):');t(i)
disp('Minimum Drop Height for Terminal Velocity (ft):'); -Yt(i)+Yo
plot(-Yt,-Vyt);xlabel('Drop Distance (ft)'); % x-axis label
ylabel('Velocity (ft/s)'); % y-axis label
Yo=4;
%Initial Vertical Position (ft)
dia=9.125/pi;
%Projectile Diameter (in)
T=40;
%Initial Angle (degrees from horizontal)
m=5.125/514.785;
%Projectile Mass (slugs)
ang=pi*T/180;
tend=20;
%
A=pi*(dia/(2*12))^2;
alpha=.5*rho*C*A;
disp('Initial Velocity Without Wind (ft/s):');wind=0;Baseball(Xo,Yo,ang,C)
disp('Initial Velocity With -10 Wind (ft/s):');wind=10;Baseball(Xo,Yo,ang,C)
disp('Initial Velocity With +10 Wind (ft/s):');wind=-10;Baseball(Xo,Yo,ang,C)
function Vo=Baseball(Xo,Yo,ang,C)
THERE=1;
for Vo=150:1:250
[t,X,Y,Vx,Vy]=Motioncalc(Xo,Yo,Vo,ang,C);
for count=1:length(Y)
if Y(count)>37
THERE=count;
end
end
if X(THERE)>344 && X(THERE)<346
break
end
end
%THERE
%X(THERE)
end
function [t,X,Y,Vx,Vy]=Motioncalc(Xo,Yo,Vo,ang,C)
%Define variables
global alpha;
global m;
global g;
global tstep;
global tend;
global wind;
t=0:tstep:tend;
Vox=Vo*cos(ang);
Voy=Vo*sin(ang);
wind2=wind*1.467; % mph to ft/s conversion
X=zeros(length(t),1);Y=zeros(length(t),1);
Vx=zeros(length(t),1);Vy=zeros(length(t),1);
Ax=zeros(length(t),1);Ay=zeros(length(t),1);
X(1)=Xo;Y(1)=Yo;Vx(1)=Vox;Vy(1)=Voy;
% Equations of motion with initial conditions
Ax(1)=-alpha/m*((Vox+wind2)^2+Voy^2)^0.5*(Vox+wind2);
Ay(1)=-g-alpha/m*((Vox+wind2)^2+Voy^2)^0.5*Voy;
% Loop to numerically solve non-linear differential equation using a
% variation of the central difference approximation method
for i=1:length(t)-1
% Update velocities using forward differences
Vx(i+1)=Vx(i)+Ax(i)*(t(i+1)-t(i));
Vy(i+1)=Vy(i)+Ay(i)*(t(i+1)-t(i));
% Update positions using the average of the speeds between
previous
% and new values (for better accuracy)
X(i+1)=X(i)+1/2*(Vx(i)+Vx(i+1))*(t(i+1)-t(i));
Y(i+1)=Y(i)+1/2*(Vy(i)+Vy(i+1))*(t(i+1)-t(i));
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% Update accelerations (equation 1 in the lab handout) for the
next
% step using the new speed values
Ax(i+1)=-alpha/m*((Vx(i+1)+wind2)^2+Vy(i+1)^2)^0.5*(Vx(i+1)+wind2);
Ay(i+1)=-g-alpha/m*((Vx(i+1)+wind2)^2+Vy(i+1)^2)^0.5*Vy(i+1);
end
end
Appendix B: Data Table
Trial
Number
Initial x
velocity
(Vx)
Initial y
velocity
(Vy)
Initial
height
(Yo)
Horizontal
distance
without
drag
Horizontal
distance
with drag
Experimental
Horizontal
Distance
1
2.954
10.125
.798
2.74
2.3299
2.299
2
4.484
10.275
.495
3.19
2.7901
2.780
3
2.699
10.301
.353
1.92
1.7993
1.785
4
2.149
7.416
.200
3.32
1.0455
3.036
Appendix C: Teamwork Breakdown
Taylor: Tracker Software, List of Symbols, Conclusion, Abstract, Post Lab #4, 5
Declan: Post Lab #6, 8, 9, 11, 12, 13
Dom: Theory and Methods,
Pre lab 1, Post Lab #1, 2, 3
Gili: Introduction, Pre Lab #2, Post Lab #7, 10, Acknowledgements
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a. Find the inverse of the model.
b. If a taxi produces a horsepower of 200, what is the torque it generates?
Solve here:
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Develop a confusion matrix for the following observations during land cover mapping
2
1
2
3
4
2
4
5
1
3
1 Sorghum
4
4
1
2
3
1
5
2
2
3
2
Maize
5
2
4
2
3
2
3
4
4
3
3 House
5
3
4
5
1
5
3
5
5
1
4 Water
2 5
1
4
3
5
1
1
4
3
5 Shop
Classified
Actual
Table of consistency ratio
Matrix order
1 2 3 4 5 6 7 8
number
RI
0
0.52 0.90
1.12
1.25
1.35
1.42
Matrix order
9
10
11
12
13
14
15
number
RI
1.46
1.49
1.52
1.54
1.56
1.58
1.59
List of formula
R = 0.5*P*17.3
M = silt(100-clay)
K = [2.1*M1.14* (104)*(12-OC)+3.25*(structure-2)+2.5*(permeability-3)]/100
Structure: 1-VFG, 2-FG, 3-medium, 4-platty
Permeability: 1-rapid, 2moderate to rapid, 3-moderate, 4-slow to moderate, 5-slow, 6- very slow
C = exp(2*ndvi/(1-ndvi))
LS = sqrt(1/22)* (0.065+0.045*s+0.0065*s²)
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62. •A 5-kg object is constrained to move along a straight
line. Its initial speed is 12 m/s in one direction, and its final
speed is 8 m/s in the
opposite
Complete the graph of
force versus time with
direction.
F (N)
(s)
appropriate values for
both variables (Figure
7-26). Several answers
are correct, just be sure
that your answer is
internally consistent.
Figure 7-26 Problem 62
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In Matlab, add J2 perturbations to your two body propagation. Comment on your findings. Also, how would you change your code if you had other things affecting the orbit. For example, solar radiation pressure, third body perturbations, or drag. Do you just add the accelerations together in the function?
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a.mheducation.com/ext/map/index.html?_con%3Dcon&external_browser%3D08&launchUrl=https%253A%252...
Check my
NOTE: This is a multi-part question. Once an answer is submitted, you will be
unable to return to this part.
The bob of a simple pendulum of length /= 40 in. is released from rest when 0 =
5°.
Assuming simple harmonic motion, determine the magnitudes of the velocity and acceleration of
the bob after the pendulum has been in motion for 1.65 s.
The magnitude of the velocity of the bob after the pendulum has been in motion for 1.65 s is
82699 ft/s.
The magnitude of the acceleration of the bob after the pendulum has been in motion for 1.65 s is
t/s2.
Menu
Tro
Dicection
In
fuel
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What mathematical relationship exists between the wave speed and the density of the medium, using the POWER trendline equation from the graph? Make your response specific (i.e., describe the full mathematical proportionality between the two variables) Feel free to use the table.
Table:
Frequency (Hz)
Density (kg/m)
Tension (N)
Speed (cm/s)
Wavelength (cm)
0.85
0.1
4.0
632.5
744.12
0.85
0.7
4.0
239.0
281.18
0.85
1.3
4.0
175.4
206.35
0.85
1.9
4.0
145.1
170.70
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Please help me. thank u!
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